Answer:
the answer is -364
Step-by-step explanation:
If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
Y= 12 - x
27 + 3( 12 - x ) = 2x
(2x+4) +(3x-1) +(x+1)=34
6x+4=34
x=5
AB=14, BC=14, AC=6
