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jekas [21]
3 years ago
14

To calculate 4 1/5% tax on $63.78, multiply 4.2 times 63.78. True or False.

Mathematics
2 answers:
nikdorinn [45]3 years ago
6 0

The answer is false


Marina86 [1]3 years ago
4 0
\bf {{ a}}\%\ of\ b \implies  \cfrac{{{ a}}}{100}\cdot b\implies {{ a}}\div 100\cdot b\qquad thus\\\\
-----------------------------\\\\
{{ 4\frac{1}{5}}}\%\ of\ 63.78 \implies  \cfrac{{{ 4\frac{1}{5}}}}{100}\cdot 63.78\implies {{ 4\frac{1}{5}}}\div 100\cdot 63.78

you tell us, what would you end up multiplying 63.78 there, to get the 4 1/5% of it?
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Answer:

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Aloiza [94]

Answer:

a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]

Step-by-step explanation:

a. -Given that:

n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64

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\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator,\bar x_m-\bar x_f is calculated by the following following:

\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}

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E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416

Hence, the margin of error is 15.7416

c. The estimator confidence interval is calculated using the following formula:

\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}

#We substitute to solve for the confidence interval using the standard deviation and sample size values in  a above:

CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]

Hence, the 99% confidence interval is [51.2884,82.7716]

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uysha [10]

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4 0
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Keith_Richards [23]

Answer:

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