Two ways:
1) guess factors(trial and error)
2) use quadratic formula.
If you use this method then a = -3, b = -6 and c = -1
x = -b +/- [sqrt(b^2 -4ac)/2a]
substituting a, b, and c into our equation we get:
x = - (-6)+/- [sqrt ((-6)^2) - 4(-3)(-1))/2 (-3)]
x = + 6 +/- [sqrt (36 -4 (3)/-6)] if I didnt make a mistake in my signs
x = + 6 +/- [sqrt (36 -12)/-6)]
x = 6 +/- [sqrt (24)/-6] but sqrt 6 x sqrt of 4 = sqrt 24 hence
x = 6 +/- [ sqrt 6 x sqrt 4 /-6] that is:
x = 6 +/- [sqrt 6 x 2 /-6 ]
so x = 6 + [sqrt 6 x 2/-6] and x = 6 - [sqrt 6 x 2/-6]
Answer:
One cup of coffee is $3.25
Step-by-step explanation:
Create a system of equations where c is the cost of a cup of coffee and d is the cost of a donut
2c + 4d = 10.5
c + 5d = 8.25
Solve by elimination by multiplying the top equation by -5 and the bottom equation by 4
-10c - 20d = -52.5
4c + 20d = 33
Add them together and solve for c
-6c = -19.5
c = 3.25
So, a cup of coffee is $3.25
Step-by-step explanation:
BODMAS
B-brackets()
O-of(multiplication)×
D-division÷
M-multiplocation×
A-addition+
S-subtraction-
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