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labwork [276]
3 years ago
9

Help with the calculus problem please

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0

The area of the region is equal to the area under the curve <em>y</em> = cos(<em>x</em>) over the interval 0 ≤ <em>x</em> ≤ <em>π</em>/6, given by the integral

\displaystyle\int_0^{\frac\pi6}\cos(x)\,\mathrm dx = \sin(x)\bigg|_0^{\frac\pi6}=\sin\left(\frac\pi6\right)-\sin(0)=\boxed{\frac12}

which follows from

• the fact that d/d<em>x</em> [sin(<em>x</em>)] = cos(<em>x</em>)

• the fundamental theorem of calculus

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Brilliant_brown [7]

Answer:

C=hypotenuse [h]=50 feet

A=[base]=40foot.

B=perpendicular [p]=?

Area =?

we have

By using Pythagoras law

p²+b²=h²

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4 0
3 years ago
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Today joelle walked at a rate of 3 miles per hour and she ran 15 minutes at a rate of 6 miles per hour.How many total miles did
svetoff [14.1K]
I added a screenshot with the complete question

<u><em>Answer:</em></u>
Total miles = 2.5 miles

<u><em>Explanation:</em></u>
<u>1- While walking:</u>
We are given that Joelle walked 20 minutes at a rate of 3 miles per hour.
This means that she walked \frac{20}{60} =  \frac{1}{3} of an hour at a rate of 3 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while walking:</u>
Distance = 3 * \frac{1}{3} = 1 mile

<u>2- While running:</u>
We are given that Joelle ran 15 minutes at a rate of 6 miles per hour
This means that she ran \frac{15}{60} =  \frac{1}{4} of an hour at a rate of 6 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while running:</u>
Distance = 6 * \frac{1}{4} = 1.5 miles

<u>3- getting the total mileage:</u>
Total distance she covered = distance while walking + distance while running
Total distance she covered = 1 + 1.5
Total distance she covered = 2.5 miles

Hope this helps :)

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3 years ago
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