A
given the 2 equations
2x + y = - 2 → (1)
x + y = 5 → (2)
subtract (2) from (1) term by term to eliminate y
(2x - x ) + (y - y ) = (- 2 - 5 )
x + 0 = - 7 ⇒ x = - 7
substitute x = - 7 in either of the 2 equations and solve for y
(2) : - 7 + y = 5 ( add 7 to both sides )
y = 5 + 7 = 12 → A
Answer:
Either strong positive or moderate positive
Step-by-step explanation:
not sure but would guess strong
Answer:
The final answers are x = 1 OR x = -3.
Step-by-step explanation:
Given the equation is x^2 -3 = -2x
Rewriting it in quadratic form as:- x^2 +2x -3 = 0.
a = 1, b = 2, c = -3.
Using Quadratic formula as follows:- x = ( -b ± √(b² -4ac) ) / (2a)
x = ( -2 ± √(4 -4*1*-3) ) / (2*1)
x = ( -2 ± √(4 +12) ) / (2)
x = ( -2 ± √(16) ) / (2)
x = ( -2 ± 4 ) / (2)
x = (-2+4) / (2) OR x = (-2-4) / (2)
x = 2/2 OR x = -6/2
x = 1 OR x = -3
Hence, final answers are x = 1 OR x = -3.
Answer:
(4, 5 )
Step-by-step explanation:
x + y = 9 → (1)
x - y = - 1 → (2)
adding the 2 equations term by term will eliminate y
2x + 0 = 8
2x = 8 ( divide both sides by 2 )
x = 4
substitute x = 4 into either of the 2 equations and solve for y
substituting into (1)
4 + y = 9 ( subtract 4 from both sides )
y = 5
solution is (4, 5 )