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tekilochka [14]
3 years ago
15

What is the product of 3/5 of 40

Mathematics
2 answers:
belka [17]3 years ago
7 0
24 would be your answer

tester [92]3 years ago
7 0
24 is the correct answer there you go
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8 0
3 years ago
Read 2 more answers
Can someone help with these two questions?
Effectus [21]

Answer:

4. x = 7

5. A

Step-by-step explanation:

you can't use a calculator ?

4.

x² = 49

x = 7

5.

sqrt(4) = 2

triple root (8) = 2

sqrt(16) = 4

only sqrt(2) is a never-ending sequence of digits without any repeating pattern after the decimal point. and that is the meaning of irrational numbers. they can never be described by an expression a/b, where a and b are integer numbers.

5 0
3 years ago
Read 2 more answers
The vertex form of the equation of a parabola is y = 2(x+ 4)2 - 21.
Ivanshal [37]

Answer:

y = 2x² + 16x + 11

Step-by-step explanation:

first foil (x + 4)² to get x² + 8x + 16

distribute 2 to get 2x² + 16x + 32

subtract 21 from 32

8 0
3 years ago
Assuming A = dominant allele that produces red-eye, a = recessive allele that produces sepia eye, B = dominant allele that produ
AURORKA [14]

Answer:

25% of probabilities

Step-by-step explanation:

A= red eye

a=sepia eye

B=longwing

b=apterous

         AB         aB

Ab     AABb     AaBb

ab      AaBb     aaBb

AABb=25%

AaBb=25%

Ab= 25%

aaBb=25%

aaBb= sepia eye with longwig

4 0
3 years ago
Solve the system by elimination. <br> -2x+2y+3z=0<br> -2x-y+z=-3<br> 2x+3y+3z=5
KengaRu [80]
-2x + 2y +  3z = 0 → 2x - 2y -   3z = 0 → 2x - 2y - 3z = 0
-2x -   1y +  1z = -3 → 2x + 1y -    1z = 3 → 2x + 1y -  1z = 3
2x +   3y + 3z = 5 →  2x + 3y + 3z = 5            -3y - 2z = -3

-2x + 2y +  3z = 0 → 2x - 2y -   3z = 0
-2x -   1y +  1z = -3 → 2x + 1y -    1z = 3 → 2x + 1y -   1z = 3
2x +   3y + 3z = 5 →  2x + 3y + 3z = 5 → 2x + 3y + 3z = 5
                                                                           -2y - 4z = -2

-3y - 2z = -3 → -6y - 4z = -6
-2y - 4z = -2 → -2y - 4z = -2
                                 -4y = -4
                                  -4     -4
                                     y = 1

  -3y - 2z = -3
-3(1) - 2z = -3
   -3 - 2z = -3
 + 3          + 3
         -2z = 0
          -2    -2
            z = 0

    -2x + 2y + 3z = 0
-2x + 2(1) + 3(0) = 0
       -2x + 2 + 0 = 0
             -2x + 2 = 0
                    - 2  - 2
                    -2x = -2
                     -2     -2
                       x = 1
              (x, y, z) = (1, 1, 0)
8 0
3 years ago
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