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MArishka [77]
3 years ago
12

Which is the axis of symmetry of a parabola with equation y^2=-8x?

Mathematics
2 answers:
Montano1993 [528]3 years ago
8 0
The same as the one i just answered y^8=2
goldfiish [28.3K]3 years ago
8 0

Answer:

x = -4

Step-by-step explanation:

Given the equation of the parabola y² = -8x, the axis of symmetry has equation to be x = c

To get the value of x from the equation, we will use the related

x = -b/2a

The equation given can be rewritten as y²+8x = 0

Comparing this with he general form of a quadratic equation

ax²+bx+c = 0

a = 1, b = 8

x = -8/2(1)

x = -8/2

x = -4

The axis of symmetry of the parabola is at x = -4.

Note that the axis of symmetry passes through the vertex of the parabola

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Answer:

the total weight is 12,483 kilos

Step-by-step explanation:

The computation of the weight is shown below:

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5 0
3 years ago
What is the value of the expression? - 16+ 12 <br>A. -28 <br>B. -4 <br>C. 4<br>D. 28​
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Answer:

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Step-by-step explanation:

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3 years ago
What is the midpoint of the line segment (-8,-7) and (-7,-8)
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3 0
3 years ago
What is the product of (2p+7)(3p+4p-3)
Alex

Answer:

The answer is C=6p3 + 29p2 + 22p – 21

Step-by-step explanation:

To calculate the product, we need to multiply each member of each multiplier:

(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3

                                   =    6p³     +     8p²    -     6p    + 21p²   +  28p   -     21

                                   = 6p³ + 8p² + 21p² + 28p - 6p -21

                                   = 6p³ + 29p² + 22p - 21

Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21

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3 years ago
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Step-by-step explanation:

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