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Airida [17]
3 years ago
10

Mrs. Wong has 144 tiles that she is going to place on her square kitchen floor. If the tiles are $3.79 each, how much did Mrs. W

ong spend on tile?
Mathematics
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

Mrs. Wong spend $545.76 on tiles.

Step-by-step explanation:

Mrs. Wong has 144 tiles that she is going to place on her square kitchen floor. If the tiles are $3.79 each, how much did Mrs. Wong spend on tile?

we are given

number of ties=144

cost of one tie=3.79 dollar

we have to find

total cost of 144 ties

for this we will multiply 144 by 3.79

multiplying 144 by 3.79 gives=144*3.79

it other words

one tile cost=$3.79

and for 144 ties cost

multiplying 144 on both sides

144 tiles cost=3.79*144=$545.76

pogonyaev3 years ago
3 0

Answer:

She will spend $545.76!

Step-by-step explanation:

To get the answer you must multiply 144 by 3.79. You will end up with $545.76


Good Luck

Please mark me BRAINLIEST

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valkas [14]

Answer:

5/40

Step-by-step explanation:

1/8 = 2/16 = 3/24 = 4/32 = 5/40

you just need to add 1 to the numerator(number on top) and 8 to the denominator(number at bottom). :)

7 0
2 years ago
16 &gt; - 8 + x<br><br> A. x &gt; 24<br><br> B. x &lt; 24<br><br> C. x &gt; 8<br><br> D. x &lt; 8
xeze [42]

Answer:

B. x < 24

Step-by-step explanation:

16 > - 8 + x

+8 > +8 + x     Add 8 to both sides

24 > x

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6 0
3 years ago
A construction zone on Interstate 15 has a speed limit of 40 mph. The speeds of vehicles passing through this construction zone
monitta

Answer:

a. The percentage of vehicles who pass through this construction zone who are exceeding the posted speed limit =90.82%

b. Percentage of vehicles travel through this construction zone with speeds between 50 mph and 55 mph= 2.28%

Step-by-step explanation:

We have to find

a) P(X>40)= 1- P(x=40)

Using the z statistic

Here

x= 40 mph

u= 44mph

σ= 3 mph

z=(40-44)/3=-1.33

From the  z-table   -1.67 = 0.9082

a) P(X>40)=

Probability exceeding the speed limit = 0.9082 = 90.82%

b) P(50<X<55)

Now

z1 = (50-44)/3 = 2

z2 = (55-44)/3= 3.67

Area for z>3.59 is almost equal to 1

From the z- table we get

P(55 < X < 60) = P((50-44)/3 < z < (55-44)/3)

     = P(2 < z < 3.67)

     = P(z<3.67) - P(z<2)

     = 1 - 0.9772

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or 2.28%

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What is the area of the shaded region?​
IRINA_888 [86]
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3 years ago
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