All categories

2 years ago

If a number is positive, then it is a whole number and an integer.

Mathematics

1 answer:

GaryK [48]2 years ago

4 0

Answer:

c then d my man I got you maybe

You might be interested in

Choose values for n and graph. f(n) = n to the second power + (-2)

Rus_ich [418]

No clue what the answer is I am not that good I am blonde
now goodbye

5 0

4 years ago

Answer for brainliest

Vikentia [17]

The answer is c

25/5 is 5

So 5>4

3 0

3 years ago

A boy has only dimes and quarters in his piggy bank. if he has 70 coins worth 12 dollars and 40 cents altogether, how many quart

dlinn [17]

Let us bear in mind the equivalent value of these coins:

One dime = $0.10

One quarter = $0.25

Let x = number of dimes

y = number of quarters

Since the boy has 70 coins in total, we can say that:

x + y = 70 (can be written as x = 70 – y)

Since the boy has a total of $12.40, we can say that:

0.10x + 0.25y = 12.40

To solve this problem, we need to solve this system of equation. We have to substitute the value of x as written in the first equation (x = 70 –y)

0.10(70 – y) + 0.25y = 12.40

7 – 0.10y + 0.25y = 12.40

0.15y = 5.40

y = 36

X = 70 – 36

X = 34

Therefore, the boys has 34 dimes and 36 quarters. To check our answer, we just have to check if his money would total $12.40.

34 dimes = $3.40

36 dimes = $9.00

Total $12.40

7 0

3 years ago

Read 2 more answers

The segment drawn from a vertex in a triangle to the midpoint of the opposite side.

AVprozaik [17]

check the picture below.

3 0

4 years ago

Read 2 more answers

Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance

lana66690 [7]

Answer:

Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20% of users develop nausea.

Let p = population proportion of users who develop nausea

So, Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Here, null hypothesis states that 20% of users develop nausea.

And alternate hypothesis states that more than 20% of users develop nausea.

The test statistics that would be used here is One-sample z proportion test statistics.

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of users who develop nausea in a sample of 241 subjects = $\frac{54}{241}$

n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0

3 years ago