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Doss [256]
3 years ago
12

Horse races are often measured in furlongs. The Kentucky Derby is 10 furlongs long, what is the distance in miles? [1 furlong =

1/8 mile]
Mathematics
2 answers:
lesya [120]3 years ago
4 0
Multiply the 1/8 mile by the number of furlongs to get the answer.
1/8 x 10/1 = 5/4 or 1.25
The answer is 5/4, 1 and 1/4, or 1.25

Hope this helps. 
Mekhanik [1.2K]3 years ago
3 0

Answer: 1.25 miles

Step-by-step explanation: 1 furlong = 1/8 mile

                                            10 = 10/8 = 1 2/8 or 1.25

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3 years ago
The probability that Latisha orders french fries at lunch is .32 and the probability that she orders a grilled cheese and fries
EastWind [94]

There is a typo error in the last part of the question. The corrected part is-

"If the probability that she orders just a grilled cheese sandwich is .76, what is the probability that she will order a grilled cheese or fries?"

Answer:

The probability that she will order a grilled cheese sandwich or fries is <u>0.43.</u>

Step-by-step explanation:

Given:

Probability of ordering fries is, P(F)=0.32

Probability of ordering cheese sandwich is, P(S)=0.76

Probability of ordering both sandwich and fries is, P(F\cap S)=0.65

Probability of ordering cheese sandwich or fries is given by the union of both the events 'F' and 'S' given as P(F\cup S).

Now, using addition theorem of probability, we get:

P(F\cup S)=P(F)+P(S)-P(F\cap S)\\P(F\cup S)=0.32+0.76-0.65\\P(F\cup S)=0.43

Therefore, probability of ordering cheese sandwich or fries is 0.43.

8 0
3 years ago
A bicycle lock has a four-digit code. The possible digits, 0 What is the probability that the lock code will begin with
nika2105 [10]

Answer:

0.1-0.6

Step-by-step explanation:

First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities

the second digit is any of the remaining 9, after having picked one. 

and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=

b. What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6

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Answer:

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