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balu736 [363]
3 years ago
12

NEED HELP. HOW DO I DO THIS,?? SHOW WORK PLEASE

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0
I'm pretty sure this is what you would do: 
5 3/16...You would multiply 5 by 16 which would be which would be 80 then add 3...83
4 7/8....4*8 = 32+7= 39
6 1/8....6*8 = 48+1= 49
3 3/4....3*4 = 12+3= 15
4 5/16....4*16 = 64+5= 69
39+49+15+69=172
172 is your answer!
Hope I helped!(:
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Step-by-step explanation:

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There are 140 legs on a planet zids have 5 legs and zods have 7 legs h=how many soulutions are there
abruzzese [7]
Number of zids=x
number of zods=y
number of zid legs=5x
number of zod legs=7y

so
5x+7y=140
try to get it into slope intercept from so you can graph is (y=mx+b)
5x+7y=140
subtract 5x from both sides
7y=140-5x
divide both sides by 7
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plug in numbers for x and get numbers for y (you can only plug in multiples of 7 for x so that there are a whole number of zids and since you are counting, x and y must never be negative)

lets try 0 for x

y=-5/7(0)+20
y=20
 so x=0 and y=20 is an answer (if you can have only one of that species)


lets try 7 for x
y=-5/7(7)+20
y=-5+20
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so x=7 and y=15 is an answer


lets try 14 for x

y=-5/7(14)+20
y=-10+20
y=10

so x=14 and y=10 is another answer


lets try 21 for x
y=-5/7(21)+20
y=-15+20
y=5

so x=21 and y=5 is another answer


lets try 28 for x
y=-5/7(28)-20
y=-20+20
y=0

so x=28 and y=0 is an answer (if there can be only one of a species)


if we go further, then y will be negative so the answers are

(x,y)
(0,20)
(7,15)
(14,10)
(21,5)
(28,0)

if it is allowed that only one species exists then there are 5 possible answers
if both must exist simultaneously, then there are only 3 answers
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Answer:

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Step-by-step explanation:

that's the answer

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