We are tasked to solved for the length of the ramp having an inclination of 15 degrees with the ground and 10 feet from the end of the ramp to the base of the building of the ground. Using trigonometric properties, we have a formula given an angle and the its opposite sides which is,
sin(Angle)=opposite/hypothenuse
hypothenuse would be the distance or the length of the ramp.
so we have,
sin(15)=10/hypothenuse
Cross-multiply, we have,
hypothenuse=10/sin(15)
using scientific calculator having a DEG mode,
hypothenuse=38.63703
Rounding of in nearest tenth we get,
hypothenuse=38.6 ft
Therefore, the ramp is 38.6 ft long
The range of a function is the set of all possible outputs.
When the quadratic functions are in standard form, they generally look like this:

If a is positive, the function opens up; if it’s negative, the function opens down. In this form, the y-coordinate of the vertex is found by evaluating f(−
). For example, consider this function:
f(x) = 
So we’re gonna do: −b/2a=−8/2(−2)=−8/−4=2
Then, we plug this in:

a is negative, so the range is all real numbers less than or equal to 5.
Learn more about range at
brainly.com/question/2264373
#SPJ4
(12+8)\ 5 + 15=19... this solution works because 12+8=20.. 20/5=4 and then 4+15=19
Answer:
Step-by-step explanation:
The domain of all polynomials is all real numbers. To find the range, let's solve that quadratic for its vertex. We will do this by completing the square. To begin, set the quadratic equal to 0 and then move the -10 over by addition. The first rule is that the leading coefficient has to be a 1; ours is a 2 so we factor it out. That gives us:

The second rule is to take half the linear term, square it, and add it to both sides. Our linear term is 2 (from the -2x). Half of 2 is 1, and 1 squared is 1. So we add 1 into the parenthesis on the left. BUT we cannot ignore the 2 sitting out front of the parenthesis. It is a multiplier. That means that we didn't just add in a 1, we added in a 2 * 1 = 2. So we add 2 to the right as well, giving us now:

The reason we complete the square (other than as a means of factoring) is to get a quadratic into vertex form. Completing the square gives us a perfect square binomial on the left.
and on the right we will just add 10 and 2:

Now we move the 12 back over by subtracting and set the quadratic back to equal y:

From this vertex form we can see that the vertex of the parabola sits at (1,-12). This tells us that the absolute lowest point of the parabola (since it is positive it opens upwards) is -12. Therefore, the range is R={y|y ≥ -12}