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kirill [66]
3 years ago
12

Which equation represents a proportional relationship? A = y = -3x + 2 B = y = -2x +4 C = y = 4x D = y = x + 7

Mathematics
1 answer:
Ratling [72]3 years ago
4 0

Answer:

<h2>C. y = 4x</h2>

Step-by-step explanation:

The equation of a proportional relationship:

y=ax\to\dfrac{y}{x}=a=const.

a - the constant of proportionality.

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Y results from something being multiplied by x , and the values are always proportional to one another. Notice that putting these points into a ratio of x-value to y-value results in 1:3 as a simplified version. So, the constant of proportionality is what x is being multiplied by to get y . In this case, it is 3 . PLEASE MARK A THE BRAIN THINGY
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3 years ago
Shenny earned $25 after babysitting for 3 hours ​
tangare [24]

Answer:

i dont know 75 dollars

Step-by-step explanation:

5 0
3 years ago
What is the range of the function g(x) = 3x^2 - 6x + 3 when the domain is defined as the set of integers, x, such that 0&lt;=x&l
kakasveta [241]

Answer:

Range is  3 <= g(x) <= 27.

Step-by-step explanation:

The range  is the values of g(x) for the given domain.

When x = 0 g(x) = 3(0)^2 - 6(0) + 3 = 3.

When x = 4 g(x) = 3(4)^2 - 6(4) + 3 =  27.

6 0
3 years ago
What type of function is y=x^2+6x+5
nata0808 [166]

Hello.

\mathrm{y=x^{2} +6x+5} is a quadratic function, because it has an \mathrm{x^{2} } (x squared, or x times x) term.

Here's what linear functions look like:

\mathrm{y=mx+b}

A graph of a linear function is a line.

Quadratic functions look like so:

\mathrm{y=ax^{2} +bx+c}

A graph of a quadratic function is a parabola.

Therefore, the given function is a quadratic function.

I hope this helps.

Have a nice day.

\boxed{imperturbability}

3 0
2 years ago
⦁ Determine if the equation represents a direct variation. .8x = 1.6y ⦁ Suppose y varies directly with x. Write a direction vari
Mkey [24]
Part A:

Given that 

0.8x=1.6y\Rightarrow x= \frac{1.6}{0.8} y=2y

Thus, x = ky where k = 2.

Therefore, the given equation is a direct variation.


Part B:

If y varies directly as x, then y = kx.

Given that y = 5 when x = 2, then

5=2k \\  \\ \Rightarrow k=\frac{5}{2} =2.5 \\  \\ \Rightarrow y=2.5x

When x = 12, y = 2.5(12) = 30.



Part C:

If y varies directly as x, then y = kx.

Given that y = 9 when x = -6, then

9=-6k \\ \\ \Rightarrow k=-\frac{9}{6} =-\frac{3}{2} \\ \\ \Rightarrow y=-\frac{3}{2}x

It can be seen that the equation above satisfies all the rows of the given table, therefore, y varies with x for the data in the question and the equation for the direct variation is y=-\frac{3}{2}x



Part 4:

If y varies directly as x, then y = kx.

Given that y = 1 when x = -2, then

1=-2k \\ \\ \Rightarrow k=-\frac{1}{2} \\ \\ \Rightarrow y=-\frac{1}{2}x

It can be seen that the equation above does not satisfies the other rows of the given table, therefore, y does not vary with x for the data in the question.
8 0
3 years ago
Read 2 more answers
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