Answer:
Tens
Step-by-step explanation:
It's in the tens place because, it's after the decimal point so don't worry about anything after the decimal. So it's just 59. 9 is the first digit making it in the ones place. So that leaves 5.
Answer: 23.4
Explanation: make the volumes equal each other with the ? as x. Then solve.
(12)(18)(32.5)=(25)(12)x
Divide both sides by 12
(18)(32.5)=25x
Solve left side
585=25x
Divide by 25
x=23.4
Answer: ∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.
Step-by-step explanation:
Given: ΔXYZ and ΔEFG such that ∠X=∠F
To prove they are congruent by using ASA or AAS conruency criteria
we need only one angle and side.
1. ∠Z ≅ ∠G(angle) and XZ ≅ FG(side)
so we can apply ASA such that ΔXYZ ≅ ΔFEG.
2. ∠Z ≅ ∠G (angle)and ∠Y ≅ ∠E (angle), we need one side which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
3. XZ ≅ FG (side) and ZY ≅ GE (side), we need one angle which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
4. XY ≅ EF(side) and ZY ≅ FG(side), not possible.
5. ∠Z ≅ ∠G(angle) and XY ≅ FE(side),so we can apply ASA such that
ΔXYZ ≅ ΔFEG.
Answer:
36
Step-by-step explanation:
![-2[-6(-4+7)]\\\\=(-2)(-6)(3)\\\\=12(3)\\\\=36](https://tex.z-dn.net/?f=-2%5B-6%28-4%2B7%29%5D%5C%5C%5C%5C%3D%28-2%29%28-6%29%283%29%5C%5C%5C%5C%3D12%283%29%5C%5C%5C%5C%3D36)
Answer:
Area = 7 square units
Perimeter = 14 units
Step-by-step explanation:
The shape is made up of 7 identical squares and, we are told the side length of each square is 1 unit.
==>Find area of the shape by calculating the area of 1 square, then multiply by the number of square used in the construction.
Thus, area of 1 square = s² = 1² = 1 square units.
Area of shape = 7 × 1 square units = 7 square units
==>Find the Perimeter of the shape by adding all the lengths of the boundary formed by the square to make up the shape.
(Check attachment to understand how we got the measurement of the boundary)
<em>The perimeter = 1 + 1 + 1 + ½ + ½ + 1 + 1 + 1½ + ½ + 1 + 1 + 4 = 14 units</em>
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