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3 years ago

Which equation represents a proportional relationship? A = y = -3x + 2 B = y = -2x +4 C = y = 4x D = y = x + 7

Mathematics

1 answer:

Ratling [72]3 years ago

4 0

Answer:

Step-by-step explanation:

The equation of a proportional relationship:

$y=ax\to\dfrac{y}{x}=a=const.$

a - the constant of proportionality.

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rodikova [14]

Y results from something being multiplied by x , and the values are always proportional to one another. Notice that putting these points into a ratio of x-value to y-value results in 1:3 as a simplified version. So, the constant of proportionality is what x is being multiplied by to get y . In this case, it is 3 . PLEASE MARK A THE BRAIN THINGY

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3 years ago

Shenny earned $25 after babysitting for 3 hours

tangare [24]

Answer:

i dont know 75 dollars

Step-by-step explanation:

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3 years ago

What is the range of the function g(x) = 3x^2 - 6x + 3 when the domain is defined as the set of integers, x, such that 0<=x&l

kakasveta [241]

Answer:

Range is 3 <= g(x) <= 27.

Step-by-step explanation:

The range is the values of g(x) for the given domain.

When x = 0 g(x) = 3(0)^2 - 6(0) + 3 = 3.

When x = 4 g(x) = 3(4)^2 - 6(4) + 3 = 27.

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3 years ago

What type of function is y=x^2+6x+5

nata0808 [166]

Hello.

$\mathrm{y=x^{2} +6x+5}$ is a quadratic function, because it has an $\mathrm{x^{2} }$ (x squared, or x times x) term.

Here's what linear functions look like:

$\mathrm{y=mx+b}$

A graph of a linear function is a line.

Quadratic functions look like so:

$\mathrm{y=ax^{2} +bx+c}$

A graph of a quadratic function is a parabola.

Therefore, the given function is a quadratic function.

I hope this helps.

Have a nice day.

$\boxed{imperturbability}$

3 0

2 years ago

⦁ Determine if the equation represents a direct variation. .8x = 1.6y ⦁ Suppose y varies directly with x. Write a direction vari

Mkey [24]

Part A:

Given that

$0.8x=1.6y\Rightarrow x= \frac{1.6}{0.8} y=2y$

Thus, x = ky where k = 2.

Therefore, the given equation is a direct variation.

Part B:

If y varies directly as x, then y = kx.

Given that y = 5 when x = 2, then

$5=2k \\ \\ \Rightarrow k=\frac{5}{2} =2.5 \\ \\ \Rightarrow y=2.5x$

When x = 12, y = 2.5(12) = 30.

Part C:

If y varies directly as x, then y = kx.

Given that y = 9 when x = -6, then

$9=-6k \\ \\ \Rightarrow k=-\frac{9}{6} =-\frac{3}{2} \\ \\ \Rightarrow y=-\frac{3}{2}x$

It can be seen that the equation above satisfies all the rows of the given table, therefore, y varies with x for the data in the question and the equation for the direct variation is $y=-\frac{3}{2}x$

Part 4:

If y varies directly as x, then y = kx.

Given that y = 1 when x = -2, then

$1=-2k \\ \\ \Rightarrow k=-\frac{1}{2} \\ \\ \Rightarrow y=-\frac{1}{2}x$

It can be seen that the equation above does not satisfies the other rows of the given table, therefore, y does not vary with x for the data in the question.

8 0

3 years ago

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