3 years ago

Find AM in the parallelogram if PN=9 and AO=4

Mathematics

1 answer:

yaroslaw [1]3 years ago

5 0

Diagonals of a parallelogram bisect each other. It is not relevant that PN=9. since AO=4 then AM=4

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Answer:

$log_{17}52.875 = log_{10}52.875 : log_{10}17}$

Step-by-step explanation:

Given

$log_{17}(52.875)$

Required

Convert to base 10

To do this, we make use of the following logarithm laws;

$log_ba = \frac{log_{10}a}{log_{10}b}$

In the given parameters;

$a = 52.875$

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Substitute these values in $log_ba = \frac{log_{10}a}{log_{10}b}$

$log_{17}52.875 = \frac{log_{10}52.875}{log_{10}17}$

Represent as a ratio

$log_{17}52.875 = log_{10}52.875 : log_{10}17}$

Hence;

$log_{17}(52.875)$ is represented as $log_{17}52.875 = log_{10}52.875 : log_{10}17}$

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