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PtichkaEL [24]
3 years ago
11

Solve 40 = 20 + 2(x-3)

Mathematics
2 answers:
Anna [14]3 years ago
7 0

Answer:

x=13

Step-by-step explanation:

40=20+2(x-3)

-20 -20

20=2(x-3)

/2   /2

10=x-3

+3    +3

x=13

Rom4ik [11]3 years ago
6 0

Answer: 19x

Step-by-step explanation:Because if you add 22 and 2 and minus 3 and add the x you get your answer 19x

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An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p
Nadya [2.5K]

Answer:

  a=-\dfrac{3+9\sqrt{3}}{52}\approx −0.357470332079

Step-by-step explanation:

Here, we assume that point A is (-1, 0) and point B is (z, 2). Since angle BAD is 60°, we have ...

  2/(z+1) = tan(60°) = √3

  z = (2/√3) -1

Putting the value of z into the equation for the parabola lets us find "a".

  2 = a(z +1)(z -5) = a(2/√3)(2/√3 -6)

Then ...

  a = 2/(4/3 -12/√3) = (6√3)/(4√3 -36)

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6 0
3 years ago
Mathematics puzzle from my calculus text book.
xenn [34]

Answer:

{ \tt{g(x) = a {x}^{2} + bx + c = 0 }} \\ { \tt{f(x) =  {a'x}^{2} + b 'x + c' = 0}} \\ { \boxed{ \bf{f(g(x)) = g(f(x))}}} : \\ { \tt{ =(  \frac{a}{a'})x {}^{2}   + ( \frac{b}{b'}) x} +  \frac{c}{c'} } = 0

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3 years ago
What was the property of equality
loris [4]

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Addition Property=For all real number X,y & Z,. if

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Four brother each bought two hotdogs and a bag of chips at the football
jeyben [28]

Answer:

A-$1.65

Step-by-step explanation:

You multiply 1.25 by 4 because each brother bought a bag of chips. Then you subtract that by the total and get $13.20 you divide that by 8 hot dog because each brother got 2 hot dogs. By dividing 8 by the  left over amount from subtracting the chips you get how much each hot dog is worth.

8 0
3 years ago
Evaluate the line integral ∫c3xy2ds, where c is the right half of the circle x2+y2=36.
Verizon [17]
We can choose x=6\cos t and y=6\cos t, so that the path C is traversed when -\dfrac\pi2\le t\le\dfrac\pi2.

Now

\displaystyle\int_C 3xy^2\,\mathrm dS=3\int_{t=-\pi/2}^{t=\pi/2}(6\cos t)(6\sin t)^2\sqrt{x'(t)^2+y'(t)^2}\,\mathrm dt
=\displaystyle648\int_{t=-\pi/2}^{t=\pi/2}\cos t\sin t^2\sqrt{36\cos^2t+36\sin^2t}\,\mathrm dt
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Taking u=\sin t, we have

=\displaystyle3888\int_{u=-1}^{u=1}u^2\,\mathrm du
=1296(1^3-(-1)^3)
=2592
7 0
4 years ago
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