Question

A coating of film n=1.33 on glass slabs (n=1.6) is 8.3×10E−5 cm thick. If white light is incident normally, which visible wavelengths are missing in the reflected light? 

Answer 1

We are given with
n1 = 1.33
n2 = 1.6
x = 8.3x10-5 cm

The angle of incident is normal, angle is 90
Using Snell's law
sin θ1 / sin θ2 = n2 / n1
Substitute the given values and solve for θ2<span />

Answer 2

Answer:

the missing wavelengths would be those that give length of $8.3 * 10-^{5}cm$

Explanation:

Data:

Let the coating of the film be n = 1.33 on glass

The refractive index = 1.6

Thickness of the slab = 8.3 × 10⁻⁵ cm

Therefore, the angles are all determined from the normal

This gives:

$\frac{sin\theta _{1} }{sin\theta _{2} } = \frac{n_{1} }{n_{2} }$

The relationship, known as Snell's law, can be used to evaluate the missing angles in the wavelength region.