A man is trapped in a room. The room has only two possible exits: two doors. Through the first door there is a room constructed
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The distance between city a and city b is 833.345 miles.
We know that
1°=60'
The distance of city a from the initial ray is calculated as
x_a=3960*tan45.46°=4024.101 miles
The distance of city b from the initial ray is calculated as
x_b=3960*tan 38.86°=3190.75 miles
Now the distance between city a and b is equal to
4024.101-3190.75=833.345 miles
This is the vertical distance between the cities.
initial speed of the racer is given as
after applied force the final speed is given as
now during this speed change the racer will cover total distance 185 m
so here we will use kinematics
now the force that chute will exert on the racer will be given as
B) here following is the strategy for solving it
1. first we used kinematics to find the acceleration of the car
2. then we used Newton's II law (F = ma) to find the force