Answer:
Δω = -6.00 rad/s
α = -2.61 m/s²
Explanation:
Step 1: Data given
A bicycle tire is spinning counterclockwise at 3.00 rad/s
Δt = 2.30 s
In theopposite (clockwise) direction, also at 3.00 rad/s
Step 2: Calculate the change in the tire's angular velocity Δω
Δω = ωf - ωi
ωf = - 3.00 rad/s
ωi = 3.00 rad/s
Δω = ωf - ωi = -3.00 - 3.00 = -6.00 rad/s
Step 3: Calculate the tire's average angular acceleration α
α = Δω / ΔT
α = -6.00 rad/s /2.30s
α = -2.61 m/s²
A negative angular acceleration means a decreasing angular velocity
Answer:
θ = 13.16 °
Explanation:
Lets take mass of child = m
Initial velocity ,u= 1.1 m/s
Final velocity ,v=3.7 m/s
d= 22.5 m
The force due to gravity along the incline plane = m g sinθ
The friction force = (m g)/5
Now from work power energy
We know that
work done by all forces = change in kinetic energy
( m g sinθ - (m g)/5 ) d = 1/2 m v² - 1/2 m u²
(2 g sinθ - ( 2 g)/5 ) d = v² - u²
take g = 10 m/s²
(20 sinθ - ( 20)/5 ) 22.5 = 3.7² - 1.1²
20 sinθ - 4 =12.48/22.5
θ = 13.16 °
Answer:
Correct option is D.
Explanation:
The size may change due to the distance from the mirror
I am 100% Sure about this answer
Answer with explanation:
The Normalization Principle states that
Given
Thus solving the integral we get
The integral shall be solved using chain rule initially and finally we shall apply the limits as shown below
Applying the limits and solving for A we get
![I=\frac{1}{k}[\frac{1}{e^{kx}}-\frac{x}{e^{kx}}]_{0}^{+\infty }\\\\I=-\frac{1}{k}\\\\\therefore A=-k](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7Bk%7D%5B%5Cfrac%7B1%7D%7Be%5E%7Bkx%7D%7D-%5Cfrac%7Bx%7D%7Be%5E%7Bkx%7D%7D%5D_%7B0%7D%5E%7B%2B%5Cinfty%20%7D%5C%5C%5C%5CI%3D-%5Cfrac%7B1%7D%7Bk%7D%5C%5C%5C%5C%5Ctherefore%20A%3D-k)
Explanation:
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