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MA_775_DIABLO [31]
3 years ago
14

Where do the electrons that form the auroras enter the magnetosphere? a. Through holes c. At the equator b. Between the magnetic

field lines d. In the magnetotail
Physics
2 answers:
marta [7]3 years ago
7 0
I think the answer is d. In the magnetotail. I hope this helps! :)
sergiy2304 [10]3 years ago
3 0

Answer:

Between the magnetic field lines.

Explanation:

The electron which forms the auroras can enter the magnetosphere through the invisible magnetic field lines. These charge particles comes from the sun as in the form of wind.

Therefore, the electrons which forms the auroras can enter the magnetosphere in between the magnetic field lines which are invisible.

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Jorge hits a drum as hard as he can, and it makes a loud sound. Then he hits the same drum with less strength, and it makes a qu
Leviafan [203]

Answer:

when he uses more force to hit the drum then its makes a louder sound so the more force you hit the drum with then the louder it is.

8 0
3 years ago
Refractive index of water is 1.3. calculate the speed of light in water.​
wolverine [178]

Answer:

The speed of light is faster in water. The Refractive index of water is 1.3 and the refractive index of glass is 1.5. From the equation n = c/v, we know that the refractive index of a medium is inversely proportional to the velocity of light in that medium. Hence, light travels faster in water.

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3 years ago
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Calcular la rapidez promedio
Vlada [557]

Answer:

  v_average = 15 m / s

Explanation:

The average speed can be found in two ways,

* taking the distance traveled and divide it by the time spent

* taking the velocities in each time interval and then finding the weighted average by the time fraction

              v_average = 1 / t_total ∑  v_{i}  t_{i}vi ti

Let's apply this last equation

               

Total time is

               t = t₁ + t₂

               t = 10 + 10 = 20   min

              v_average = 10/20 10 + 10/20 20

              v_average = 10/2 + 20/2

              v_average = 15 m / s

7 0
3 years ago
The spring of a spring balance is 6.0 in. long when there is no weight on the balance, and it is 8.4 in. long with 4.0 lb hung f
Sergeeva-Olga [200]

Answer:

W = 55.12 J

Explanation:

Given,

Natural length = 6 in

Force = 4 lb,  stretched length = 8.4 in

We know,

F = k x

k is spring constant

4 = k (8.4-6)

k = 1.67 lb/in

Work done to stretch the spring to 10.1 in.

W =k\int_{6}^{10.1} x

W = \dfrac{k}{2}[x^2]_6^{10.1}

W = \dfrac{1}{2}\times 1.67\times (10.1^2-6.0^2)

W = 55.12 J

Work done in stretching spring from 6 in to 10.1 in is equal to 55.12 J.

3 0
3 years ago
John is hiking and notices a small stream of water flowing down the side of the mountain. What part of the water cycle is John o
Alexus [3.1K]

Answer: Runofff

Explanation: because it said that it is going down the side of the mountain

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2 years ago
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