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MA_775_DIABLO [31]
3 years ago
14

Where do the electrons that form the auroras enter the magnetosphere? a. Through holes c. At the equator b. Between the magnetic

field lines d. In the magnetotail
Physics
2 answers:
marta [7]3 years ago
7 0
I think the answer is d. In the magnetotail. I hope this helps! :)
sergiy2304 [10]3 years ago
3 0

Answer:

Between the magnetic field lines.

Explanation:

The electron which forms the auroras can enter the magnetosphere through the invisible magnetic field lines. These charge particles comes from the sun as in the form of wind.

Therefore, the electrons which forms the auroras can enter the magnetosphere in between the magnetic field lines which are invisible.

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A body in simple harmonic motion has a displacement x that varies in time t according to the equation x = 5cos(π t + π/3) , wher
zhuklara [117]

Answer:

1/2 Hz

Explanation:

A simple harmonic motion has an equation in the form of

x(t) = Acos(\omega t - \phi)

where A is the amplitude, \omega = 2\pi f is the angular frequency and \phi is the initial phase.

Since our body has an equation of  x = 5cos(π t + π/3) we can equate \omega = \pi and solve for frequency f

2\pi f = \pi

f = 1/2 Hz

7 0
3 years ago
Read 2 more answers
A player kicks a soccer ball from ground level and sons at flying at an angle of 30° at a speed of 26MS how far did the ball tra
RSB [31]

Answer:

Explanation:

60 meters is he answer for this question

7 0
3 years ago
Describe how a neutral material becomes attracted to a negatively charged object brought near it.
Naddik [55]

Answer:

Electric force

Explanation:

It’s like static stuff

3 0
2 years ago
A car travels along a highway with a velocity of 24 m/s, west. The car exits the highway; and 4.0 s later, its instantaneous vel
zloy xaker [14]

Answer:

4.25 m/s^{2}

Explanation:

Change in velocity considering the x component will be

Final velocity-Initial velocity

\triangle v_x= 16cos 45^{\circ}-24=-12.6862915 m/s

Change in velocity considering the y component will be

Final velocity-Initial velocity

\triangle v_y= 16sin 45^{\circ}-0=11.3137085 m/s

Resultant change in velocity=\sqrt {(-12.6862915 m/s)^{2}+(11.3137085 m/s)^{2}}=16.9982938 m/s

Acceleration= change in velocity per unit time hence

a= \frac {16.9982938}{4}=4.24957345\approx 4.25 m/s^{2}

5 0
3 years ago
If you were in charge of designing a wire to carry electricity across your city, state or province, which of
Anon25 [30]

Answer:

Thin, aluminium and buried underground.

Explanation:

When it comes to electrification of a state or province, some characteristics of the wire to use must be considered. This would help to minimize and avoid power loss and wire burns.

i. The wire to use should be thin, and a quite number can be twisted one against the other so as to increase the surface area for heat dissipation.

ii. Aluminium wire is more preferable for this project. It has a high melting point, and reduces energy loss.

iii. Burying the wire underground through an insulator is the best choice, though expensive but would preserve the wire from external influence.

7 0
2 years ago
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