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4 years ago

(x+3)(x+2) can some one help with this one please (factoring trinomials)

Mathematics

1 answer:

Licemer1 [7]4 years ago

5 0

Make it a trinomial by using the FOIL method.
First
Inside
Outside
Last

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A silo is not the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cu

Gnom [1K]

Answer:

$7803.72

Step-by-step explanation:

We have been given that a silo is in the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cubic meter. We are asked to find the total cost to fill the silo with soybeans.

First of all, we will find the volume of silo using volume of cone formula.

$\text{Volume of cone}=\frac{1}{3}\pi r^2 h$ , where,

r = radius

h = Height

We know that radius is half the diameter, so radius of silo would be $r=\frac{3}{2}=1.5$ .

$\text{Volume of cone}=\frac{1}{3}\pi (1.5\text{ m})^2 (8)\text{ m}$

$\text{Volume of cone}=\frac{1}{3}\pi\times 2.25\text{ m}^2 (8)\text{ m}$

$\text{Volume of cone}=\pi\times 0.75\text{ m}^2 (8)\text{ m}$

$\text{Volume of cone}=\pi\times 6\text{ m}^3$

$\text{Volume of cone}=18.8495559\text{ m}^3$

Now we will multiply total volume by $414 to find total cost.\

$\text{Total cost of soybeans}=\$414 \times 18.8495559$

$\text{Total cost of soybeans}=\$7803.7161426$

$\text{Total cost of soybeans}\approx \$7803.72$

Therefore, it will cost $7803.72 to fill the silo with soybeans.

5 0

3 years ago

Need help with a couple of geometry word problems. Giving 100 points, tysm if you help :)

dlinn [17]

Answer:

Hope it helps

Step-by-step explanation:

1: B

2: B

3: D

4: C

5: A

6 0

3 years ago

CAN SOMEONE PLSSS HELP MEE IM STUCK ON THIS QUESTION PLSS!!!

TiliK225 [7]

Answer:

20 each girl

Step-by-step explanation:

40 divided by 2 girls is 20

8 0

3 years ago

A right triangle has a leg measuring 52 m and a hypotenuse measuring 63 m. find the length of the other leg.

tangare [24]

By Pythagoras Theorem,
the length of the other leg= (63^2-52^2)^1/2
hope this helps :)

4 0

3 years ago

Can someone help me with this problem

Alex_Xolod [135]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(-3, 0) , B(3, 2)

$AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}$

A(-3, 0), D(-2, -3)

$AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

AB = CD and AD = BC

The area of a rectangle:

$A=(AB)(AD)$

Substitute:

$A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20$

The perimeter of a rectangle:

$P=2(AB+AD)$

Substitute:

$P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}$

4 0

3 years ago