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Eva8 [605]
4 years ago
14

How do I solve w(x)=4x+5; find w(-8)?

Mathematics
1 answer:
madam [21]4 years ago
6 0
W(x) = 4x + 5

w(-8) = 4(-8) + 5 = -32 + 5 = -27
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Find the total in the account with the following facts monthly contributions =$180 employer matching 25% interest rate 4.99% yea
algol13

Answer:

The amount that will be in the account after 38 years is $ 36811,05

Step-by-step explanation:

a)

For resolved this exercise used the next equation

R(1-(1 + i)--) Ap = ... (1)

Ap = Amount in account

R = Paid monthly

i = Monthly interest rate

t = Months for paid

Dates

i=- 2.05% 12 = 0,1708% = 0.0017

The interest is divided for 12 because is annual and the formula is mensual

t = 15yearsx12 = 180 months

             R = 220$

R(1-(1 + i)-) Ap =

220(1-(1 + 0.0017)-180) Ap = 0.0017

162,04 Ap=0.0017

Ap = 95321,855

The amount that will be in the account after 15 years is $ 95,321.85

b)

R(1-(1 + i)--) Ap = ... (1)

Ap = Amount in account

R = Paid monthly

i = Monthly interest rate

t = Months for paid

i=- 4,99% -= 0,415% = 0.0041

The interest is divided for 12 because is annual and the formula is mensual

t = 38yearsx12 = 456 months

             R = 180$

R(1-(1 + i)-) Ap =

Ap = 180(1-(1 + 0.0041) -456 0.0041

Ap = 36811,055

The amount that will be in the account after 38 years is $ 36811,05

4 0
3 years ago
1/2 and a fraction equivalent to 2/6
makkiz [27]

Answer:1/2 if you multiply 2 to the top number then multiply 3 with the bottom

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
an article when sold at a profit of 5% yields rupees 50 more than when sold at a loss of 5% what was the cost price of the artic
ziro4ka [17]

I'm going to assume that the question should say “at a profit of 5%”.

Restate question in the form of a equation.

Let C = the cost price of the item.

C + 0.705 C = C - 0.05 C + Rs 50

0.05 C = - 0.05 C + Rs 50

0.10 C = Rs 50

C = Rs 500

The cost price of the item is Rs 500

I hope this help you

6 0
3 years ago
City Community College plans to increase its enrollment capacity to keep up with an increasing number of student applicants. The
aivan3 [116]
The given above may be modeled by the arithmetic sequence with initial value (I) 2200 and common difference (d) of 70. The number of applicants every year can be written by the equation,
                          at = a1 + (n - 1) x d
From the given above, n is equal to 4. This corresponds to the term which is 3 years from now. 
                           at = 2200 + (4 - 1) x 70 = 2410
Thus, the enrollment capacity would be 2410 students. 
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3 years ago
Graph 3(8-4x)<6(x-5)
Zinaida [17]

First simplify this inequality:

3(8-4x)

Now you can graph this inequality. Draw the vertical dashed line x=3 and shade the region to the right from this line. This is exactly the region that represents the solution of inequality (see attached diagram for details).

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