All enzymatic active sites will become occupied by substrate
Answer:
See figure 1 and 2
Explanation:
In this case, we can start with the general reaction. Acetanilide with bromine in acetic acid we will produce <u>p-bromo-acetanilide</u> (See figure 1).
In the reaction mechanism, we have as first step the attack of the double bond in the benzene ring to one of the Br atoms in bromine () and a positive carbon will be produced in benzene. This positive charge can be moved inside of the benzne ring producing the r<u>esonance structures A, B and D</u>. Resonance structure C is produced when a double bond is generating between the "N" atom and the carbon in the benzene ring.
The final step in the mechanism is when we remove the "H" atom in structure A to produce again the double bond.
See figure 2
I hope it helps!
Answer:
B
Explanation:
Generally, when you dilute something, your goal is to thin your concentration. Even if you added a solute, if your goal is dilution, it will make the concentration decrease.
The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g
<h3>Avogadro's hypothesis </h3>
6.02×10²³ formula units = 1 mole of CuF₂
But
1 mole of CuF₂ = 101.5 g
Thus,
6.02×10²³ formula units = 101.5 g of CuF₂
<h3>How to determine the mass of 8.94×10²² formula units of CuF₂</h3>
6.02×10²³ formula units = 101.5 g of CuF₂
Therefore,
8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³
8.94×10²² formula units = 15.07 g of CuF₂
Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂
Learn more about Avogadro's number:
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