The formula for molarity is: mol/L. so it would be 2.0 mol/ 6.0 L.
the answer is: .33 M
hope this helps!
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Answer:
The correct answer is option B.
Explanation:

Moles of
= 40 mol
Moles of NaOH = 48 mol
According to reaction, 3 moles of NaOH reacts with 2 moles 
Then ,48 moles of NaOH will reacts with:
of 
Then ,40 moles of
will reacts with:
of NaOH
As we can see that 48 moles of sodium will completey react with 32 moles of nitrogen tribromide.
Moles left after reaction = 40 mol - 32 mol = 8 mol
Hence, the
is an excessive reagent.