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luda_lava [24]
3 years ago
10

Can you please convert this equation: 8^(1\2)x^(1\2)y^(3\4)

Mathematics
1 answer:
liq [111]3 years ago
8 0
So, that's
{8}^{ \frac{1}{2} }  \times  {x}^{ \frac{1}{2} }  \times  {y}^{ \frac{3}{4} }

*Helpful To Know
{5}^{ \frac{1}{2} }  =  \sqrt{5} \\  {5}^{ \frac{1}{3} }  =  \sqrt[3]{5}  \\ {5}^{ \frac{1}{4} }  =  \sqrt[4]{5}    \\   {5}^{ \frac{3}{2} }  =  \sqrt{ {5}^{3} } \:  \: or \:   {( \sqrt{5} )}^{3}
----------------------------------------------------------------

*Assuming that you want to covert to radicals

( \sqrt{8} )( \sqrt{x} )( \sqrt[4]{ {y}^{3} } )
*Simplify

( \sqrt{8x} )( \sqrt[4]{ {y}^{3} } )
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Function : y = 4sin(2x-π)

<h3>Basic's:</h3>

f(x) = A * g(Bx - C) + D where C/B is phase shift, D is vertical shift.

<h3><u>For this trigonometric function</u></h3>

Identify: B = 2, C = π, D = 0

<u />

<u>Horizontal shift</u>:

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<u>Vertical shift</u>:

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