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professor190 [17]
3 years ago
8

Why do doctors worry more about a fever of a couple of degrees Celsius than a fever of a couple of degrees Fahrenheit

Chemistry
2 answers:
weeeeeb [17]3 years ago
8 0
Because Celcius is a larger amount than Fahrenheit. The units are farther apart.
alisha [4.7K]3 years ago
3 0
Celcius is a smaller number than celcius but the same. pretty much, 100 degress farenheit equals to 37.7778 degrees celcius. 
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Write the formula and determine the percent by mass of the salt in barium hydroxide octahydrate *
user100 [1]

Answer:

315.51g/mol

Explanation:

137(33 + (16.00 + 1.01) 2 + 8 [1.01 (2) + 16.00] = 315.51g/mol

7 0
2 years ago
What are the mole ratios of hydrazine
juin [17]

mole ratios of hydrazine should be 1:2. I could be wrong. Are there any options to choose from?

5 0
2 years ago
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

from the relation:

number of moles = \frac{mass}{atomic mass of 1 mole}

rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

3 0
3 years ago
Which of the following is an example of maintaining homeostasis? A. Learning B. Jumping C. Shivering D. Smiling
yawa3891 [41]

Answer:

Shivering.

Explanation:

Homeostasis is the bodies need to keep things at a normal. When you are cold you shiver to produce body heat and get back to normal  

5 0
2 years ago
An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is t
Pachacha [2.7K]
The density of CO2 getting from experiment is 0.1/0.056 = 1.79 g/L. The percent error of this is (1.96 -1.79)/1.96*100%=8.67%. So the approximate percent error is 8.67%.
3 0
2 years ago
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