At what colored dot does the map indicate the steepest location? Provide an explanation for your reasoning below.

Number of grams in 4 mols of cu(no2)2

Drupady [299]

151.55 x 4 you have to add the molar masses for each element together.

6 0

3 years ago

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Which of these solutes raises the boiling point of water the most?

sergey [27]

Answer:

D. ionic sodium phosphate (Na3PO4)

Explanation:

Molecule for molecule, the solute that raises the boiling point of water the most is the one that makes the most particles in the solution. Lithium chloride breaks up into two ions (Li+ and Cl-). So does sodium chloride (Na+ and Cl-). Molecular molecules don't break up at all, so sucrose has only 1 particle per molecule. Sodium phosphate makes 4 total particles (3 Na+ ions and 1 PO4^3-). And magnesium bromide would make 3 particles (1 Mg2+ and 2 Br-). So the most is 4.

6 0

3 years ago

How many grams of water can be produced when 11.7 moles of ethane (C2H6) react with excess oxygen gas?

Elina [12.6K]

Answer: 631.8 g

Explanation:

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

It can be seen from the balanced chemical equation, 2 moles of ethane reacts with 7 moles of Oxygen gas to produce 4 moles of carbon dioxide and 6 moles of water.

Ethane is the limiting reagent as it limits the formation of product.

Thus, if 2 moles of ethane produce 6 moles of water.

11.7 moles moles of ethane produce= $\frac{6}{2}\times 11.7=35.1 moles$ of water.

Mass of water= no of moles $\times$ Molar mass

Mass of water= 35.1 $\times$ 18g/mol= 631.8 g

4 0

3 years ago

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When 60 mL of 0.22 M NH4Cl is added to 60 mL of 0.22 M NH3, relative to the pH of the 0.10 M NH3 solution the pH of the resultin

densk [106]

Answer:

Will be more acidic

Explanation:

The equilibrium of NH3 in water is:

NH3(aq) + H2O(l) ⇄ NH4⁺(aq) + OH⁻(aq).

Where equilibrium constant, Kb, is:

Kb = 1.85x10⁻⁵ = [NH4⁺] [OH⁻] / [NH3]

From 0.10M NH3, the reaction will produce X of NH4⁺ and X of OH⁻ and Kb will be:

1.85x10⁻⁵ = [X] [X] / [0.10M]

1.8x10⁻⁶ = X²

X = 1.34x10⁻³ = [OH⁻]

As pOH = -log[OH⁻] = 2.87

And as pH = 14 - pOH

pH of the 0.10M NH3 is 11.13

Now, to find the pH of the NH4Cl and NH3 we need to use H-H equation for bases:

pOH = pKb + log [NH4⁺] / [NH3]

<em>Where pKb is -log Kb = 4.74 and [] are moles of both compounds.</em>

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Moles of [NH4⁺] = [NH3] = 60mL, 0.060L*0.22M = 0.0132moles:

pOH = 4.74 + log [0.0132] / [0.0132]

pOH = 4.74

pH = 14 - 4.74 = 9.26

That means the pH of the resulting solution will be more acidic

7 0

3 years ago

Phosphorus has three electrons in its 3p sublevel and sulfur has four. Phosphorus should have the lower ionization energy but it

Nadya [2.5K]

Answer:

B

Explanation:

First of all it is important to know that a half filled orbital is particularly stable. In phosphorus all the electrons occur singly in the 3p sublevel minimizing inter electronic repulsion hence it is more difficult to remove an electron from this energetically stable arrangement. In sulphur, electrons are paired in one of the 3p orbitals thereby lowering the energy of that level due to instability caused by interelectronic repulsion between two electrons in the same orbital.

8 0

2 years ago