Answer:
D 4P +3O₂ → 2 P₂O₃
Explanation:
In this problem, we need to convert the mass of phosphorus and oxygen to moles trying to find the ratio of reaction (The moles of P that reacts per mole of O₂):
<em>Moles P:</em>
12.4g P * (1mol P / 31g) = 0.4 moles
<em>Moles O₂:</em>
9.6g * (1mol / 32g) = 0.3 moles
The ratio of reaction is:
0.4 mol / 0.3 mol = 1.33 = 4 moles of P / 3 moles of O₂
That means 4 moles of P react with 3 moles of O₂ and the reaction that represents this ratio is:
<h3>D 4P +3O₂ → 2 P₂O₃</h3>
Answer:
delocalised electrons
Explanation:
they are called delocalised electrons because that can move freely in the molecule
Answer:
It is 20. g HF
Explanation:
H2 + F2 ==> 2HF ... balanced equation
Since the question is asking us to find the mass of product formed, we will want to first convert the molecules of H2 into moles of H2 (we could do this at the end of the calculations, but it's just as easy to do it now).
moles of H2 present (using Avogadro's number):
3.0x1023 molecules H2 x 1 mole H2/6.02x1023 molecules = 0.498 moles H2
From the balanced equation, we see that 1 mole H2 produces 2 moles HF. Therefore, we can now find the theoretical mass of HF produced from 0.498 moles H2:
0.498 moles H2 x 2 moles HF/1 mol H2 = 0.996 moles HF formed.
The molar mass of HF = 20.01 g/mole, thus...
0.996 moles HF x 20.01 g/mole = 19.93 g HF = 20. g HF formed (to 2 significant figures)
Answer:
you sure it is the right sign your using
