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3 years ago

Help with this question, please!

Mathematics

1 answer:

jonny [76]3 years ago

6 0

Answer:

The last choice is the one you want.

Step-by-step explanation:

Simply take the x coordinate and subtract 4, then do the same with the y coordinate since the vector movement is <-4, -4>. The first coordinate F is <4,0>. Subtract 4 from both of those coordinates and end up at <0, -4>. The second coordinate G is <1, 3>. Subtract 4 from both of those and end up at <-3, -1>. The third coordinate H is <2, 6>. Subtract 4 from both of those and end up at <-2, 2>. The last coordinate I is <4, 2>. Subtract 4 from both of those and end up at <0, -2>.

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Find y when x = 3 of the equation for y=2x+12

ser-zykov [4K]

Answer:

y = 18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

y = 2x + 12

x = 3

Step 2: Evaluate

Substitute in x: y = 2(3) + 12
Multiply: y = 6 + 12
Add: y = 18

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3 years ago

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Answer:

Step-by-step explanation:

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GalinKa [24]

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Solve:C=10d + 5n for n

katovenus [111]

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hope this helps

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3 years ago

A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects

Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let X denote the number of green candies.

The probability of green candies is, p = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, n = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable X follows a binomial distribution with parameter n = 30 and p = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

$P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328$

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

= 0.17228 + 0.17946 + 0.15328

= 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

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3 years ago