Answer:
The density of the bar of gold is 19.32 grams per cubic centimeter .
Step-by-step explanation:
Formula
As given
A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.
As 1 kilogram = 1000 gram
Than convert 13.949 kilograms into grams.
13.949 kilograms = 13.949 × 1000 grams
= 13949 grams
Mass = 13949 grams
Volume = 722 cubic centimeter
As put in the formula
Density = 19.32 grams per cubic centimeter (Approx)
Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .
HETY is a parallelogram.
HT and EY are diagonals. We know that diagonals divides the parallelogram into two equal parts.
So ar(HET) = ar(HTY)
And, ar(HEY) = ar(EYT) now, in AHET, diagonal EY bisects the line segment HT and also the AHET,
∴ar(AHOE) = ar(AEOT)
Similarly in AETY
ar(ΔΕΟΤ) = ar(ΔΤΟΥ)
And in AHTY,
ar(ATOY) = ar(AHOY)
That means diagonals in parallelogram divides it into four equal parts.
Hence Proofed.
Answer:
![\left[\begin{array}{ccc}11&15&-17\\-1&-4&-4\\17&15&-22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%2615%26-17%5C%5C-1%26-4%26-4%5C%5C17%2615%26-22%5Cend%7Barray%7D%5Cright%5D)
Option D will be your answer
hope it helps...
have a great day!!
Step-by-step explanation:
focus(p) is on the x axis= -1
vertex=(0,0)
parabola equation----- (y-h)^2 =4p(x-k)
(h, k)=(0,0)
(y-0)^2 =4(-1)(x-0)
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y^2 = -4x
that is the answer
Answer:
y = (x/(1-x))√(1-x²)
Step-by-step explanation:
The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:
x = r·cos(θ)
y = r·sin(θ)
x² +y² = r²
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r = sec(θ) -2cos(θ)
r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)
r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²
(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations
x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor
y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)
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The attached graph shows the equivalence of the polar and rectangular forms.
