Answer:
For 200t per day, the volume of gas is <em>2.76×10⁵ m³ </em>
For 300t per day, the volume of gas is <em>4.13×10⁵ m³ </em>
Explanation:
It is stated that 1t = 10³ kg
Therefore,
For 200t per day:
The number of moles of SO₂ is calculated as follows,
n(SO₂)= m/(molar mass)
where
- m is the mass of SO₂
- molar mass is the sum of the molecular masses of Sulphur (S) and Oxygen (O)
Thus,
<em>n(SO₂)= (200×10³kg)/(64×10⁻³kg.mol⁻¹)</em>
<em> = 3.13×10⁶ mol</em>
Therefore, the volume is determined as follows,
V= nRT/P
where
- n is the number of moles of SO₂
- R is the gas constant
- T is the temperature in Kelvin (K)
- P is the pressure of the gas
Thus,
To convert from degrees celcius to Kelvin, we 273 to the given temperature.
<em>V= ((3.13×10⁶ mol)(0.08206dm³.atm.mol⁻¹.K⁻¹)(800+273K))/1 atm</em>
<em> = 2.76×10⁸ dm³</em>
For the answer to be in m³, we divide by 10³. Thus,
<em>V= 2.76×10⁵ m³</em>
For 300t per day:
The number of moles of SO₂ is calculated as follows,
n(SO₂)= m/(molar mass)
where
- m is the mass of SO₂
- molar mass is the sum of the molecular masses of Sulphur (S) and Oxygen (O)
Thus,
<em>n(SO₂)= (300×10³kg)/(64×10⁻³kg.mol⁻¹)</em>
<em> = 4.69×10⁶ mol</em>
Therefore, the volume is determined as follows,
<em>V= nRT/P</em>
where
- n is the number of moles of SO₂
- R is the gas constant
- T is the temperature in Kelvin (K)
- P is the pressure of the gas
Thus,
To convert from degrees celcius to Kelvin, we 273 to the given temperature.
<em>V= ((4.69×10⁶ mol)(0.08206dm³.atm.mol⁻¹.K⁻¹)(800+273K))/1 atm</em>
<em> = 4.13×10⁸ dm³</em>
For the answer to be in m³, we divide by 10³. Thus,
<em>V= 4.13×10⁵ m³</em>