All categories

2 years ago

1. What is the purpose of the advertisement?

Chemistry

2 answers:

ASHA 777 [7]2 years ago

6 0

Answer:

For enlightenment, development and making people understand the usefulness of the product

sveta [45]2 years ago

5 0

Answer:

AKA "AD"AND ADS EXPLAIN WAYS IN WHICH THE PRODUCT IS USEFUL ... PLEASE MARK ME AS BRAINLIST

You might be interested in

20 POINTS!! please helps me with this word bank!! due today!! you can use a word more than once please help

Bogdan [553]

Answer:

zoom in please i cant see

Explanation:

7 0

3 years ago

Read 2 more answers

Consider the following reaction between mercury(II) chloride and oxalate ion.

Alina [70]

<u>Answer:</u> The rate law of the reaction is $\text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2$

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)$

Rate law expression for the reaction:

$\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b$

where,

a = order with respect to $HgCl_2$

b = order with respect to $C_2O_4^{2-}$

Expression for rate law for first observation:

$3.2\times 10^{-5}=k(0.164)^a(0.15)^b$ ....(1)

Expression for rate law for second observation:

$2.9\times 10^{-4}=k(0.164)^a(0.45)^b$ ....(2)

Expression for rate law for third observation:

$1.4\times 10^{-4}=k(0.082)^a(0.45)^b$ ....(3)

Expression for rate law for fourth observation:

$4.8\times 10^{-5}=k(0.246)^a(0.15)^b$ ....(4)

Dividing 2 from 1, we get:

$\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2$

Dividing 2 from 3, we get:

$\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1$

Thus, the rate law becomes:

$\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2$

3 0

3 years ago

Tell me a hypothesis for the corrosion experiment for iron nails?

Nastasia [14]

The more acidic the substance is, the more the iron nails will corrode (this obviously depends on what your experiment is but hope this helped in some way)

5 0

3 years ago

What did Ernest Rutherford’s gold foil experiment demonstrate about atoms ?

Alchen [17]

Answer:

Their positive charge is located in the small nucleus

Explanation:

Ernest Rutherford performed the gold foil experiment in 1911 where he used alpha particles generated from a radioactive source to bombard a thin gold foil.

In his experiment, he observed that the bulk of the alpha particles passed through the gold foil, just a tiny fraction was deflected back. To explain his findings, Rutherford proposed that an atom is made of positively charged centre where nearly all the mass is concentrated called nucleus. Surrounding the nucleus is a large space containing electrons.

4 0

3 years ago

Read 2 more answers

A car traveling with constant speed travels 150km in 7200 s. What is the speed of the car

neonofarm [45]

75km/hr

A car traveling with constant speed travels 150km in 7200 s. What is the speed of the car

4 0

3 years ago

1. What is the purpose of the advertisement?​

1. What is the purpose of the advertisement?