Answer: The concentration of KOH for the final solution is 0.275 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
where,
n = moles of solute
= volume of solution in ml = 150 ml
moles of solute =
Now put all the given values in the formula of molality, we get
According to the dilution law,
where,
= molarity of stock solution = 1.19 M
= volume of stock solution = 15.0 ml
= molarity of diluted solution = ?
= volume of diluted solution = 65.0 ml
Putting in the values we get:
Therefore, the concentration of KOH for the final solution is 0.275 M
Answer:
7 mL
Explanation:
To prepare a solution by dilution of another one, we can use the equation:
C1V1 = C2V2
where <em>C</em> is the concentration, <em>V</em> is the volume, <em>1</em> is the initial solution, and <em>2</em> the final solution. V represents the total volume. K₂CrO₄ dissolver by:
K₂CrO₄ → 2K⁺ + CrO₄⁻²
So, 1 mol of K₂CrO₄ results in 1 mol of CrO₄⁻², the in a solution of 8.75x10⁻⁴M of CrO₄⁻², it will be 8.75x10⁻⁴M of K₂CrO₄, so the volume of the stock solution will be:
1.25x10⁻³xV1 = 8.75x10⁻⁴x10
V1 = (8.75x10⁻³)/(1.25x10⁻³)
V1 = 7 mL
TRUE
common phenomenon for all unstable uranium atoms
q3 not sure maybe The atomic masses of elements X and Y will always equal the exact atomic mass of Z.
high temperatures
FALSE
Answer:
The process by which a body of water becomes enriched in dissolved nutrients (such as phosphates) that stimulate the growth of aquatic plant life usually resulting in the depletion of dissolved oxygen.
Answer:
Explanation:
Hello,
In this case, with the given information, we can identify the limiting reactant and compute the theoretical yield for the undergoing chemical reaction:
Thus, with the given concentrations and volumes we compute the available moles of silver acetate:
Then, the moles of silver acetate that are consumed by 35 mL of 1.0 M calcium chloride:
Therefore, since there are less available moles, it is the limiting reactant, for that reason, the theoretical yields of both calcium acetate and silver acetate are:
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