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poizon [28]
3 years ago
5

A photo that is 4 in wide and 6 in high is enlarged to a poster that is 3ft wide and 4 1/2 ft high what is the ratio of the widt

h of the photo to the width of the poster
Mathematics
2 answers:
ankoles [38]3 years ago
8 0
1:9 would be the ratio
Aleksandr-060686 [28]3 years ago
7 0

Answer:

Required ratio in the simplest form = 1 : 9

Step-by-step explanation:

Width of photo = 4 inches

Height of the photo = 6 inches

Width of the poster = 3 feet

Now, 1 feet = 12 inches

So, Width of the poster = 3 × 12 = 36 inches

Height of the poster = 4.5 feet

                                  = 54 inches

We need to find the ratio of the width of the photo to the width of the poster

⇒ Required Ratio = 4 : 36

⇒ Required ratio in the simplest form = 1 : 9

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Sum of two sides always greater than the third side

If c is the smallest number, then

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If c is the largest number, then

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3 years ago
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aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

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Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

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Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

4 0
3 years ago
Dan draws a circle with a radius of 8 inches. Question 1 Part A: What is the circumference of Dan's circle, inches? If needed, r
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Answer:

The circumference of Dan's circle is approximately 50.27 inches.

Step-by-step explanation:

The length of the circumference (s), measured in inches, is determined by the formula:

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If we know that r = 8\,in, then the length of the circumference is:

s = 2\pi\cdot (8\,in)

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The circumference of Dan's circle is approximately 50.27 inches.

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