Tanα=y/x
α=arctan(y/x), we are given the point (3.2, 6.2) so:
α=arctan(6.2/3.2)°
α=arctan(1.9375)°
α≈62.7° (to nearest tenth of a degree)
Answer:
Step-by-step explanation:
y^2 + x^2 = 65
y + x = 7......x = 7 - y
y^2 + (7 - y)^2 = 65
y^2 + (7 - y)(7 - y) = 65
y^2 + 49 - 7y - 7y + y^2 = 65
2y^2 - 14y + 49 = 65
2y^2 - 14y + 49 - 65 = 0
2y^2 - 14y - 16 = 0
2(y^2 - 7y - 8) = 0
2(y + 1)(y - 8) = 0
y + 1 = 0 y - 8 = 0
y = -1 y = 8
solution :
y = -1...........y + x = 7.....-1 + x = 7......x = 7 + 1......x = 8........(8,-1)
y = 8........y + x = 7.....8 + x = 7......x = 7 - 8........x = -1........(-1,8)
Until now, given a function <span>f(x)</span>, you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given <span>f(x) = 2x + 3</span>, you could find <span>f(y2 – 1)</span> by plugging<span> y2 – 1</span> in for x to get <span>f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1</span>.
In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of<span> (x, y)</span><span> points </span>
<span>Hope this awnsers your question</span>
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alright so first ur trying to find adjacent so use cos which is adjacent/hypotenuse you know the angle of c is 90 because it is a right angle
so it gonna be
cos(90)= AC/5
5*cos(90)= AC
5*0=AC
side AC = 0
Answer:
i dont know
Step-by-step explanation:
