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3 years ago

| 1). What number is 40% of 50?

Mathematics

1 answer:

ipn [44]3 years ago

7 0

40% of the number 50 is 20

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Use the identity (x+y)(x−y)=x2−y2 to find the difference of two numbers if the sum of the numbers is 12 and the difference of th

Natalka [10]

Answer:

The difference of two numbers using identity $(x+y)(x-y)=x^2-y^2$ is 4.

Step-by-step explanation:

Given: The sum of the numbers is 12 and the difference of the squares of the numbers is 48.

To find the difference of two numbers using identity $(x+y)(x-y)=x^2-y^2$

Let the two numbers be a and b, then

Given that the sum of the numbers is 12

that is a + b = 12 .........(1)

Also, given the difference of the squares of the numbers is 48.

that is $a^2-b^2=48$ ..........(2)

Using given identity $(x+y)(x-y)=x^2-y^2$

We have $(a+b)(a-b)=a^2-b^2$

Substitute the known values, we have,

$12(a-b)=48$

Divide both side 12 , we have,

$(a-b)=4$

Thus, the difference of two numbers using identity $(x+y)(x-y)=x^2-y^2$ is 4.

8 0

3 years ago

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