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MA_775_DIABLO [31]

2 years ago

8

Libby needs to make 1/2 of her chili for the school's chili contest. If Libby usually needs 1/2 a cup of corn for her chili reci

pe, how much corn will she need for the chili contest? Write a division equation and multiplication equation to show this.

1 answer:

ryzh [129]2 years ago

5 0

Answer:

1/4

Step-by-step explanation:

1/4 x 2 = 1/2

1/2 divided by 2 is 1/4

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What is the x-coordinate of point P on the coordinate grid?

AlladinOne [14]

-1.5 is your answer, your welcome

3 0

3 years ago

Read 2 more answers

Please help me with this problem please

11111nata11111 [884]

9514 1404 393

Answer:

shortest: 11 1/8 in
longest: 11 3/8 in

Step-by-step explanation:

It should be no surprise that the shortest allowable length is the nominal length less the full allowed tolerance:

11 1/4 - 1/8 = 11 1/8 . . . inches

__

Likewise, the longest allowable length is the nominal length plus the maximum tolerance:

11 1/4 + 1/8 = 11 3/8 . . . inches

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Of course, you know that 1/4 = 2/8, so adding or subtracting 1/8 gives the fractions shown above.

5 0

2 years ago

Factor this polynomial 6x^2 + 19x – 7.

kondaur [170]

Answer:

(3x-1) (2x+7)

8 0

2 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

$-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)$

$-\text{cos} \left(\theta\right)$

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

$\text{sec}(-\theta)=\text{sec}(\theta)$

And, $\text{sec}(\theta)=-0.73$

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0

3 years ago

Para festeja su cumpleaños,Nancy compró 15 paquetes de pizzetas. Si cocinó 288 pizzetas, cuántos paquetes completos le quedaron?

Lorico [155]

Answer:

Nancy consumió 12 paquetes de pizzetas y le quedaron 3 paquetes completos.

Step-by-step explanation:

En primer lugar, debemos descomponer el número total de pizzas como una multiplicación de números primos. Al realizar la descomposición factorial tenemos que:

$288 = 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3$

Entonces, los familia de divisores de 288 es el siguiente conjunto:

$D_{288} = \{2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 72, 96, 144 \}$

Si tanto la cantidad de paquetes de pizzetas y la cantidad cocinada de pizzetas son números enteros y positivos, siendo la última mucho mayor. Entonces, la cantidad de pizzetas debe ser un número entero y la cantidad de paquetes gastados menor a la cantidad de paquetes comprados y el número entero más cercano a esa cantidad. Entonces, concluimos que Nancy se gastó 12 paquetes de pizzetas, quedándole 3 paquetes completos.

6 0

3 years ago