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Alchen [17]
3 years ago
10

You are a particle physicist at the Large Hadron Collider who is tasked with designing an apparatus to separate annihilation pro

ducts (such as pions) from proton-antiproton collisions. Because positive and negative charges deflect differently in a magnetic field, you plan to use a magnetic field to separate these products. As a starting point, in which you ignore interaction effects and assume a known velocity, you decide to explore a beam of coincident positively and negatively charged pions, each of mass in and charge +lel and -del, respectively. These pions travel between two square sheets of a known number N of densely-packed parallel current-carrying wires, each of length L and individual current 1. Determine whether the currents in the different sheets should be in the same or opposite direction to create a magnetic field between the sheets. Then, determine whether the pion beam should be parallel or perpendicular to the wires as it travels between the sheets. Ignoring fringing effects, how strong must the wire current be so that the pions are separated by a distance of one-hundredth of the sheet length as they exit the plates?

Physics
1 answer:
JulijaS [17]3 years ago
4 0

Find solution in the attachments

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The statement that no two electrons in the same atom can have the same four quantum numbers is a restatement of
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A radar station sends out a 250000 Hz sound wave at a speed of 340 m/s. The sound wave bounces off a weather ballon and returns
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Answers:

a)The balloon is 68 m away of the radar station

b) The direction of the balloon is towards the radar station

Explanation:

We can solve this problem with the Doppler shift equation:

f'=\frac{V+V_{o}}{V-V_{s}} f  (1)

Where:

f=250,000 Hz is the actual frequency of the sound wave

f'=240,000 Hz is the "observed" frequency

V=340 m/s is the velocity of sound

V_{o}=0 m/s is the velocity of the observer, which is stationary

V_{s} is the velocity of the source, which is the balloon

Isolating V_{s}:

V_{s}=\frac{V(f'-f)}{f'}  (2)

V_{s}=\frac{340 m/s(240,000 Hz-250,000 Hz)}{240,000 Hz}  (3)

V_{s}=-14.16 m/s (4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.

Now that we have the velocity of the balloon (hence its speed, the positive value) and the time (t=4.8 s) given as data, we can find the distance:

d=V_{s}t (5)

d=(14.16 m/s)(4.8 s) (6)

Finally:

d=68 m (8) This is the distance of the balloon from the radar station

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