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3 years ago

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Physics

1 answer:

Over [174]3 years ago

5 0

Answer:

$\boxed {\boxed {\sf 5.22 \ m}}$

Explanation:

Gravitational potential energy is the energy an object possesses due to its position. It is calculated using the following formula:

$E_P=mgh$

Where m is the mass, g is the acceleration due to gravity, and h is the height.

The object has a mass of 8.72 kilograms. Assuming this occurs on Earth, the acceleration due to gravity is 9.8 meters per second squared. The object gains 446 Joules of potential energy.

Let's convert the units of Joules. This makes the process of canceling units simpler later on. 1 Joule is equal to 1 kilogram meter squared per second squared. The object gains 446 J, which is equal to 446 kg *m²/s².

EP= 446 kg*m²/s²
m= 8.72 kg
g= 9.8 m/s²

Substitute the values into the formula.

$446 \ kg*m^2/s^2 = 8.72 \ kg * 9.8 \ m/s^2 *h$

Multiply on the right side of the equation.

$446 \ kg*m^2/s^2 = 85.456 kg*m/s^2 *h$

We are solving for the height, so we must isolate the variable h. It is being multiplied by 85.456 kg*m/s². The inverse operation of multiplication is division, so we divide both sides by this value.

$\frac{ 446 \ kg*m^2/s^2}{85.456 kg*m/s^2} = \frac{85.456 kg*m/s^2 *h}{85.456 kg*m/s^2}$

$\frac{ 446 \ kg*m^2/s^2}{85.456 kg*m/s^2} =h$

The units of kg*m/s² cancel, leaving meters as our unit.

$\frac{ 446 }{85.456 } \ m =h$

$5.2190601011 \ m =h$

The original measurements of mass and potential energy have 3 significant figures, so our answer must have the same.

For the number we calculated, that is the hundredths place. The 9 in the thousandths place to the right tells us to round the 1 up to a 2.

$5.22 \ m \approx h$

The object was lifted to a height of approximately 5.22 meters.

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just olya [345]

<h2>Answer: Gravitational attraction </h2>

Gravity force causes the clouds of dust and gas to form a protostar. As this attraction force is responsible for gathering and compressing the existing elements in the cloud of gas and dust, heating them during this process.

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4 0

3 years ago

vA 61.2-kg circus performer is fired from a cannon that is elevated at an angle of 57.8 ° above the horizontal. The cannon uses

dsp73

Answer:

The effective spring constant of the firing mechanism is 1808N/m.

Explanation:

First, we can use kinematics to obtain the initial velocity of the performer. Since we know the angle at which he was launched, the horizontal distance and the time in which it's traveled, we can calculate the speed by:

$v_0_x=\frac{x}{t}\\ \\v_0\cos\theta=\frac{x}{t}\\\\v_0=\frac{x}{t\cos\theta}$

(This is correct because the horizontal motion has acceleration zero). Then:

$v_0=\frac{20.8m}{(2.60s)\cos57.8\°}\\\\v_0=15.0m/s$

Now, we can use energy to obtain the spring constant of the firing mechanism. By the conservation of mechanical energy, considering the instant in which the elastic band is at its maximum stretch as t=0, and the instant in which the performer flies free of the bands as final time, we have:

$E_0=E_f\\\\U_e=K\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\\implies k=\frac{mv^2}{x^2}$