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faltersainse [42]
3 years ago
8

The diagram illustrates the movement of sound waves between an observer and a race car. As the race car drives away from the obs

erver, notes that the sound from the car gets quieter and the pitch lowers. Which statement is the MOST plausible question the observer might ask to explain the
phenomenon she experiences?
A. Why does the sound of the engine change as the car drives away?
B. What is the effect of the change in speed of the car and the pitch of the sound?
C. What is the relationship between the volume of the sound and the pitch of the sound
of the car?
D. How do changes in frequency and amplitude affect the pitch of the sound generated
by the car?
Physics
1 answer:
Andrei [34K]3 years ago
6 0
I believe the answer is d
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The figure shows a 1 cm cube that has a mass of 1 gram. Calculate the density of the cube in kg/m³.
dolphi86 [110]
Density = 1 g/cm^3 = 1000 Kg/m^3
3 0
3 years ago
If y^2= 3.249 x 10^-11, y = ?
Leni [432]

Answer:

Scientific Notation: 3.45 x 10^5

E Notation: 3.45e5

5 0
3 years ago
Read 2 more answers
When you boil potatoes, will your cooking time be reduced with vigorously boiling water instead of gently boiling water? (Direct
lara [203]

Answer:

The cooling time will not be reduced.

Explanation:

The time to cook is virtually the same in both types, vigorously and gently boiling water.

The reason cooking of spaghetti  calls for vigorously boiling water is to keep the pasta agitated so that they do not stick to one another.

The temperature of boiling water is the same for both vigorously boiling water and gently boiling water, therefore there will be little time difference in when the potatoes will cook when it is done with vigorously boiling water than when it is cooked with gently boiling water.

However cooking potatoes in vigorously boiling water may cause the water to dry up on time and the potatoes get burnt.

8 0
3 years ago
A student at a window on the second floor of a dorm sees her physics professor walking on the sidewalk beside the building. she
klasskru [66]
Refer to the diagram shown below.

In order for the balloon to strike the professor's head, th balloon should drop by 18 - 1.7 = 16.3 m in the time at the professor takes to walk 1 m.
The time for the professor to walk 1 m is
t = (1 m)/(0.45 m/s) = 2.2222 s

The initial vertical velocity of the balloon is zero.
The vertical drop of the balloon in 2.2222 s is
h = (1/2)*(9.8 m/s²)*(2.2222 s)² = 24.197 m

Because 24.97 > 16.3, the balloon lands in front of the professor, and does not hit the professor.

The time for the balloon to hit the ground is
(1/2)*(9.8)*t² = 18
t = 1.9166 s

The time difference is 2.2222 - 1.9166 = 0.3056 s
Within this time interval, the professor travels 0.45*0.3056 = 0.175 m
Therefore the balloon falls 0.175 m in front of the professor.

Answer: 
The balloon misses the professor, and falls 0.175 m in front of the professor.

8 0
3 years ago
Given Vout = 17.33 vpp and R1 = 3 kΩ, find the value of RF required to provide Av = 4.33. (Round your answer to 2 decimal places
Olenka [21]

Answer:

The magnitude of V_{2} is 4 V and phase of input voltage is zero

Explanation:

Given:

Output voltage V_{out} = 17.33

Resistance R_{1} = 3 kΩ

Voltage gain A_{v} = 4.33

For finding feedback resistance we use gain equation

Gain equation for non inverting op-amp is given by,

     A_{v} = 1+\frac{R_{f} }{R_{1} }

   4.33 = 1+ \frac{R_{f} }{3 k }

     R_{f} ≅ 10 kΩ

For finding input voltage we use,

   A_{v} = \frac{V_{out} }{V_{2} }

    V_{2} = \frac{17.33}{4.33}

    V_{2} = 4 V

The Phase of V_{2} is zero because output voltage phase is 360°

Therefore, the magnitude of V_{2} is 4 V and phase of input voltage is zero

7 0
3 years ago
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