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anastassius [24]

3 years ago

7

The Mercury Freedom 7 weighed about 2,400 pounds.It flew in 1961.The Gemini 7 capsule,which flew in 1965,weighed about 37.5% mor

e.How much does it weigh?

1 answer:

denpristay [2]3 years ago

5 0

Answer:

3300 lb

Step-by-step explanation:

The multiplier for weight is 1 +37.5% = 1.375 = 11/8. The Gemini capsule weighed about ...

(11/8)(2400 lb) = 3300 lb

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The outside of a picture frame measures 14 in and 20 in 196in^2 of the picture shows find the thickness of the frame

LuckyWell [14K]

The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width.
Area = Length x Height
Area = (20 in) x (14 in)
Area = 280 in²

We are given that the area is only equal to 192 in². We subtract this value from the computed area.
Difference = 280 in² - 192 in²
difference = 88 in²

This area is equal to the area of the hollow space inside the frame. That is equal to,
height = 20 in - 2x
length = 14 in - 2x

The area,
88 = (20 - 2x)(14 - 2x)

Simplify the right hand side of the equation.
88 = 280 - 68x + 4x²

Divide the equation by 4,
22 = 70 - 17x + x²

Transposing,
x² - 17x - 48 = 0
The factors of the equation is 58.2.

Thus, the thickenss is equal to 58.2 in

5 0

3 years ago

Find the surface area of the composite figure.

GuDViN [60]

The answer of this equation is 8cm I did the math

5 0

2 years ago

For each day , select the number of hours worked. <br><br>HELP! THE ANSWERS ARE IN THE BOX THINGY!

Strike441 [17]

Answer:

Monday's answer is 7 1/6

8 0

3 years ago

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Therefore, The conversion of unit is $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

3 0

3 years ago

astraxan [27]

7.5 %

Step-by-step explanation:

We by finding how far from the mean the 999 volume caps are, using z score;

Z = (x – μ) / σ

Z = (999 – 998) / 7

Z = 0.143

We use the z-table to find the confidence levels;

= 85%

= 0.85

Since we are finding proportion of bottles have volumes greater than 999

mL;

1 – .85 = .15

0.15/2 = 0.075

= 7.5%

5 0

2 years ago