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lora16 [44]
3 years ago
10

The outside of a picture frame measures 14 in and 20 in 196in^2 of the picture shows find the thickness of the frame

Mathematics
1 answer:
LuckyWell [14K]3 years ago
5 0
The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width. 
             Area = Length x Height
              Area = (20 in) x (14 in) 
              Area = 280 in²

We are given that the area is only equal to 192 in². We subtract this value from the computed area.
         Difference = 280 in² - 192 in²
               difference = 88 in²

This area is equal to the area of the hollow space inside the frame. That is equal to,
      height = 20 in - 2x
      length = 14 in - 2x

The area,
               88 = (20 - 2x)(14 - 2x)

Simplify the right hand side of the equation.
             88 = 280 - 68x + 4x²

Divide the equation by 4,
            22 = 70 - 17x + x²

Transposing,
                x² - 17x - 48 = 0
The factors of the equation is 58.2. 

Thus, the thickenss is equal to 58.2 in
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The answer is <span>Maureen's body eliminated the antibiotic faster than Ken's body.</span>
3 0
2 years ago
A bakery offers a sale price of $3.50 for 4 muffins. What is the price per dozen?
Elena-2011 [213]
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5 0
2 years ago
The main cable of a suspension bridge forms a parabola, described by the equation y = a(x - h)2 + k, where y is the height in fe
nirvana33 [79]
Refer to the diagram shown below.

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That is,
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Also, because the distance between the supports is 90 ft, therefore
y(0) = 6 ft, and y(90) = 6 ft
That is,
a(-h)² + k = 6                 (2)
a(90 - h)² + k = 6          (3)

From (2) and (3), obtain
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Therefore
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Answer:
The equation for the cable is
y = - 0.005(x - 45)² + 16.125 

A graph of the solution verifies that the solution is correct.

6 0
3 years ago
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