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pav-90 [236]
4 years ago
12

Melinda wants to reduce her expenses so she can balance her budget. Which variable expense can Melinda easily adjust?

Mathematics
2 answers:
sattari [20]4 years ago
7 0
B. Because you can easily just eat at home and avoid paying to eat

salantis [7]4 years ago
3 0
The answer would be B, eating out. if she eats at home instead of eating out, she can save a lot of money, and the other options are things you can't cut into the funding for
let me know if you have any other questions
:)
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PLEASE ANSWER FAST!!!! On Friday, Susan bought a dress for 35% off the regular price of $70.00. The next day, the dress that Sus
attashe74 [19]

Answer:

She would have saved 14 dollars more

Step-by-step explanation:

Hope this helps and plz mark brainliest :)

6 0
3 years ago
Read 2 more answers
How does this work?????
ankoles [38]

Answer:

x = 4\sqrt{5}

Step-by-step explanation:

Since the triangle is right, solve for x using Pythagoras' identity, that is

x² = 8² + 4² = 64 + 16 = 80

Take the square root of both sides

x = \sqrt{80} = \sqrt{16(5)} = \sqrt{16} × \sqrt{5} = 4\sqrt{5} ← exact value



3 0
3 years ago
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
4 years ago
I need help ASAP
GaryK [48]

Answer:

500

Step-by-step explanation:

Define listed price = C

Based on the term, to have the balance on both plan, the equation is 30+90%C = 80+80%C

  1. 30+0.9C=80+0.8C
  2. 0.1C=50
  3. 1C = 500
6 0
3 years ago
PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!
maxonik [38]

The number in parenthesis after f is the x coordinate. Basically, it says which y coordinate is tied with an x value. In choice a, it says that when x is 0 y is 3, etc.

So, you can look at the graph to see which answer choice has a point from the graph. Choice a says (0,3), and that does not match. Choice b says (5,-1) and that does match. So the answer is B.

*(x,y)*

5 0
4 years ago
Read 2 more answers
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