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emmainna [20.7K]
3 years ago
14

Subtract 8 y^2 − 5 y + 7 from 2 y^2 + 7 y + 1 1 The answer is: −6y ^2 +12y+4

Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

\large\boxed{-6y^2+12y+4}

Step-by-step explanation:

(2y^2+7y+11)-(8y^2-5y+7)\\\\=2y^2+7y+11-8y^2-(-5y)-7\\\\=2y^2+7y+11-8y^2+5y-7\qquad\text{combine like terms}\\\\=(2y^2-8y^2)+(7y+5y)+(11-7)\\\\=-6y^2+12y+4

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You and your friend mix water and cirtic acid. You add 3 cups of citrtic acid for every 16 cups of water Your friend adds 2 cups
Vlad [161]

Answer:

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Step-by-step explanation:

Given:

Two friends mix water and citric acid.

One (Let A) add 3 cups of citric acid for every 16 cups of water and another (Let B)adds 2 cups of citric acid for every 12 cups of water.

Now, we have to find that whose mixture is more acidic means:-

Solution:

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B adds 2 cups of citric acid for every 12 cups of water = \frac{2}{12}

Now, to find that who mix more citric acid in the mixture, firstly we will equalize the denominator of both fraction by taking LCM so that can be compare easily.

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16 - 16, 32, <u>48</u>, 64, 80, 96....

12 - 12, 24, 36, <u>48, </u>60, 72.......

For friend A - \frac{3\times3}{16\times3} =\frac{9}{48}

For friend B - \frac{2\times4}{12\times4} =\frac{8}{48}

<em>We found that in terms of 48 cups of water, friend A mixes 9 cups of acid while friend B mixes 8 cups of acid, means A is adding more acid than B and</em> hence friend A's mixture is more acidic.

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