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k0ka [10]
3 years ago
14

Solve using the Quadratic Formula. 3x2 - 7x - 3 = 0

Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Answer:

\displaystyle x_1=\frac{7+ \sqrt{85}}{6}\approx 2.70\\\displaystyle x_2=\frac{7- \sqrt{85}}{6}\approx -0.37

Step-by-step explanation:

<u>Quadratic Formula</u>

Given the second-degree equation:

ax^2+bx+c=0

The solutions of the equation can be obtained by applying the formula:

\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

The equation to solve is:

3x^2-7x-3=0

Which means the values of the coefficients are: a=3, b=-7, c=-3. Substituting the values in the formula:

\displaystyle x=\frac{-(-7)\pm \sqrt{(-7)^2-4(3)(-3)}}{2(3)}

\displaystyle x=\frac{7\pm \sqrt{49+36}}{6}

\displaystyle x=\frac{7\pm \sqrt{85}}{6}

There are two real solutions for this equation:

\displaystyle x_1=\frac{7+ \sqrt{85}}{6}

\displaystyle x_2=\frac{7- \sqrt{85}}{6}

The approximate values of both roots are:

x_1\approx 2.70

x_2\approx -0.37

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What number is being factored in this factor tree? <br><br>A.72<br> B.180 <br>C.216<br> D.324
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7 0
3 years ago
A.
Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

f(x) = x^{2} + 3x - 1

So

a = 1, b = 3, c = -1

\bigtriangleup = 3^{2} - 4*1*(-1) = 13

x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3

x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0
3 years ago
1 Which type of data is best represented using a line plot?
irakobra [83]

Answer:

#1) D frequency data that can be plotted on a number line ; #2) A Sarah read twice as many chapters Wednesday as Monday, C Sarah read more than four chapters on two days, F Sarah read at least three chapters on four days, and H The total number of chapters Sarah read on the weekend was the same as the total number she read on the weekdays.

Step-by-step explanation:

#1) A line plot shows the frequencies of data.  It is displayed over a number line; this makes the best choice for the answer "frequency data that can be plotted on a number line."

#2) We can see that Sarah read 2 chapters on Wednesday and 1 chapter on Monday.  This is twice as many chapters.

She read more than 4 chapters on both Saturday and Sunday.

She read 3 or more chapters on Tuesday, Friday, Saturday and Sunday.

The total number of chapters she read on the weekend was 5+6 = 11.  The total number of chapters she read on the weekdays was 1+3+2+2+3 = 11.  These are the same.

4 0
3 years ago
Read 2 more answers
How do you graph y=-1.5<img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20" id="TexFormula1" title=" x^{2} " alt=" x^{2} " align
lorasvet [3.4K]
y=-1.5 x^{2} +6 \\ \\ x=-3 \Rightarrow y=-1.5*(-3)^2+6 =-1.5*9+6=-13.5+6=-7.5\\ \\x=-2 \Rightarrow y=-1.5*(-2)^2+6 =-1.5*4+6=-6+6=0\\ \\x=-1 \Rightarrow y=-1.5*(-1)^2+6 =-1.5*1+6=-1.5+6=-4.5\\ \\x=0 \Rightarrow y=-1.5*0^2+6 =6

x=1 \Rightarrow y=-1.5*(1)^2+6 =-1.5+6=-4.5\\ \\ x= 2 \Rightarrow y=-1.5*2^2+6 =-1.5*4+6=-6+6=0\\ \\x=3 \Rightarrow y=-1.5*3^2+6 =-1.5*9+6=-13.5+6=-7.5


6 0
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