To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
6n + 9 = -3n <u>-21 -6</u>
<u>6n</u> + 9 = <u>-3n</u> -27
+3n +3n
9n <u>+9</u> = <u>-27</u>
-9 -9
<u>9n</u> = <u>-36</u>
<u>Divide by 9 on both sides</u>
n = -4
Area of a circle= 2 times pi times radius squared
A= 2 <span>π r^2
A=2(3.14)(97mm)^2= 609.16 mm^2</span>
I think the best answer would be so