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3 years ago

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The quotient of two negative integers results in an integer.How does the value of the quotient compare to the value of the origi

nal two integers?

1 answer:

Aleksandr-060686 [28]3 years ago

4 0

It is the inverse of the two added together

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Rationalize the denominator.

AlekseyPX

Hello and Good Morning/Afternoon!

<u>Let's take this problem step-by-step</u>:

<u>What the problem asks for:</u>

⇒ to rationalize the denominator

⇒ rationalize means that you multiply the numerator and

demonimator by the denominator

<u>Let's put that into action</u>:

$\frac{\sqrt{a +1}-2 }{\sqrt{a+1}+2 } * \frac{\sqrt{a +1}+2 }{\sqrt{a+1}+2 }\\=\frac{a +1-4 }{a+1+4\sqrt{a+1}+4 } \\=\frac{a-3}{a+4\sqrt{a+1}+5 }$ <== <u>Answer</u>

<u></u>

Hopefully that helps!

4 0

1 year ago

In the diagram line mn and jk are parallel and are intersected by line at

Katena32 [7]

There is a lack of a diagram to go along with this question...

8 0

3 years ago

Read 2 more answers

Perpendicular to y=2x+9 and has the point (4,-1)

Wewaii [24]

Answer: y = $-\frac{1}{2}$ x + 1

Step-by-step explanation:

First, we will find the slope. The slope of perpendicular lines are negative reciprocals.

In this case, the first slope is 2. The negative of 2 is -2, and the reciprocal of -2 is $-\frac{1}{2}$ .

Now, we will plug in this new slope, the point given, and solve for the <em>b</em>, or the y-intercept.

y = <em>m</em>x + <em>b</em>

(-1) = ( $-\frac{1}{2}$ )(4) + <em>b</em>

-1 = -2 + <em>b</em>

1 = <em>b</em>

Lastly, we will write our equation.

y = <em>m</em>x + <em>b</em>

y = $-\frac{1}{2}$ x + 1

The line is y = $-\frac{1}{2}$ x + 1, or y = 1 - $\frac{x}{2}$ .

4 0

2 years ago

Read 2 more answers

What is the solution to the equation 8 - 2b = -2/3(12b + 6)?

Delvig [45]

<span>8 - 2b = -2/3(12b + 6)
8 - 2b = -8b -4
8 + 4 = -8b + 2b
12 = -6b
b = -12/6
b = -2

So, your final answer is b = -2</span>

8 0

3 years ago

\large -\frac{2}{3}x+3=\frac{2}{3}x+\frac{1}{3}

german

Answer:

$\boxed {x = 2}$

Step-by-step explanation:

Solve for the value of $x$ :

$-\frac{2}{3}x + 3 = \frac{2}{3}x + \frac{1}{3}$

-Take $\frac{2}{3}x$ and subtract it from $-\frac{2}{3}x$ :

$-\frac{2}{3}x + 3 -\frac{2}{3}x = \frac{2}{3}x - \frac{2}{3}x + \frac{1}{3}$

$-\frac{4}{3}x + 3 = \frac{1}{3}$

-Subtract both sides and convert $3$ to a fraction:

$-\frac{4}{3}x + 3 - 3 = \frac{1}{3} - 3$

$-\frac{4}{3}x = \frac{1}{3} - \frac{9}{3}$

Since both $\frac{1}{3}$ and $\frac{9}{3}$ have the same denominator, then you would subtract the numerator:

$-\frac{4}{3}x = \frac{1 - 9}{3}$

$-\frac{4}{3}x = \frac{8}{3}$

-Multiply both sides by $-\frac{3}{4}$ , which is the reciprocal of $-\frac{4}{3}$ :

$x = \frac{8}{3} (-\frac{3}{4})$

$x = \frac{-8(-3)}{3 \times 4}$

$x = \frac{24}{12}$

-Divide $24$ by $12$ :

$x = \frac{24}{12}$

$\boxed {x = 2}$

So, therefore, the value of $x$ is $2$ .

5 0

3 years ago