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Fiesta28 [93]
3 years ago
6

What is 3/4 gallon in quarts?

Mathematics
1 answer:
Basile [38]3 years ago
5 0

Answer:

3 quarts = 3/4 gallon

Step-by-step explanation:


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I need help ASAP PLEASEEE!
sergeinik [125]

Answer:

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Step-by-step explanation:

- 18 >  - 5x + 2 \geqslant  - 48 \\ ( - 18 - 2) >  - 5x \geqslant ( - 48 - 2) \\  - 20 >  - 5x \geqslant  - 50  \\ \\  \frac{ - 20}{ - 5}  > x \geqslant  \frac{ - 50}{ - 5}  \\  \\ 4 > x \geqslant 10

6 0
3 years ago
A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co
zubka84 [21]

Answer:

a) i The company should buy 40 gallons from dairy I and 60 gallons from dairy

ii) What is the maximum amount of​ butterfat? The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b.The excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

Step-by-step explanation:

a. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of​ butterfat?

From the question, we are told that:

Milk from dairy I costs ​$2.40 per​ gallon, Milk from dairy II costs ​$0.80 per gallon.

Let's represent:

Number of gallons of Milk from dairy I = x

Number of gallons of Milk from dairy II = y

At most ​$144 is available for purchasing milk.

$2.40 × x + $0.80 × y = 144

2.40x + 0.80y = 144........ Equation 1

x + y = 100....... Equation 2

x = 100 - y

2.40(100 - y) + 0.80y = 144

240 - 2.4y + 0.80y = 144

-1.60y = 144 - 240

-1.6y = -96

y = -96/-1.6

y = 60

From Equation 2

x + y = 100....... Equation 2

x + 60 = 100

x = 100 - 60

x = 40

Therefore, since number of gallons of Milk from dairy I = x and number of gallons of Milk from dairy II = y

The company should buy 40 gallons from dairy I and 60 gallons from dairy

II. What is the maximum amount of​ butterfat?

From the question

Dairy I can supply at most 50 gallons averaging 3.9​% ​butterfat,

50 gallons = 3.9% butterfat

40 gallons =

Cross Multiply

= 40 × 3.9/50

= 3.12%

Dairy II can supply at most 90 gallons averaging 2.9​% butterfat.

90 gallons of milk = 2.9% butter fat

60 gallons of milk =

Cross Multiply

= 60 × 2.9%/90

=1.9333333333%

≈ 1.93%

The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b. The solution from part a leaves both dairy I and dairy II with excess capacity. Calculate the amount of additional milk each dairy could produce.

Excess capacity of Diary I =

50 gallons - 40 gallons = 10 gallons

Excess capacity of Diary II =

90 gallons - 60 gallons = 30 gallons

Therefore, the excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

3 0
3 years ago
3x^2 - 4x - 5x^2 + 8x <br> simplify it please
Levart [38]

3x^2 - 4x - 5x^2 + 8x

  • Set up

-2x^2 + 4x

  • Combine like terms

2x(-x + 2)

  • Take out a common factor

2x(2 - x)

  • Rearrange to remove a starting negative coefficient inside the parentheses

The simplification is \boxed{2x(2 - x)}.

3 0
3 years ago
30 points if u answer
Paladinen [302]

Answer:

c

Step-by-step explanation:

you have vertical angles are equal then ED=AB

                                                           and CD=CB

                                                                      SAS

                                                   we want<u> </u><u>CE=CA</u>   <u>(C)</u>

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3 years ago
Subtract (12x+9) from the sum of (5x^2+8x+6) and (8x^2+6x-6)
shepuryov [24]
<span>(5x^2+8x+6) + (8x^2+6x-6) - </span><span>(12x+9)
= </span>5x^2 + 8x+  6 +  8x^2 + 6x - 6 - 12x - 9
= 13x^2 + 2x - 9

answer
13x^2 + 2x - 9
7 0
3 years ago
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