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Reika [66]
4 years ago
6

A student is applying to Harvard and Dartmouth. If the student is accepted at Dartmouth, the probability of being accepted at Ha

rvard is 40%. If the student is not accepted at Dartmouth there is an 80% of non-acceptance at Harvard. There is a 50% chance of being accepted at Dartmouth. What is the probability a student is accepted at both Harvard and Dartmouth?

Mathematics
1 answer:
adell [148]4 years ago
6 0
I made a probability tree. Pls. see attachment. 

Based on the probability tree I made, below are the probabilities

Probability of a student accepted at both Dartmouth and Harvard is:
50% x 40% = 20%

Probability of a student accepted at Dartmouth but not Harvard is:
50% x 60% = 30%

Probability of a student not accepted at Dartmouth but accepted in Harvard is:
50% x 20% = 10%

Probability of a student not accepted in both schools is:
50% x 80% = 40%

As you can see, these probabilities total 100%

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Graph the function with the given domain. Then identify the range of the function. y = -6; domain: x ≥ 5
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3 years ago
Read 2 more answers
A luxury liner leaves a port on a bearing of 110 degrees and travels 8.8 miles. It then turns due west and travels 2.4 miles. Ho
myrzilka [38]

Answer:

Distance= 6.6 miles

Bearing= N 62.854°W

Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

Using cosine rule

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X² =8.8²+2.4²-2(8.8)(2.4)cos20

X²= 77.44 + 5.76-(39.69)

X²= 43.51

X= √43.51

X= 6.596

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Let's determine the angles within the triangle using sine rule

2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

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Angle c= 180-20-7.146

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For the bearing

110+7.146= 117.146

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Bearing= N 62.854°W

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3 years ago
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