No, in order for the lines to be parallel, the slopes have to be the same, it does not matter what the slopes are as long as they are the same slope. The lines could still be parallel if the slopes are negative.
You need to first set up the equation:
It would look like 90 divided by 360 multiplied by the given
circumference which is 72 cm.
So 90 / 360 x 72
Simply the fraction above, it will give us:
¼ x 72
So the answer would be 18 cm that is the length of DE (minor
arc)
Perimeter = 2(10+20) = 60feet
60ft fencing material is needed
Using the formula:
V= 1/6 πd^3
V ≈ 1838.78
Answer:
7/25
Step-by-step explanation:
θ lies in quadrant ii
so 2θ lies in quadrant iv
csc θ=5/3
sin θ=3/5 (sin θ=1/csc θ)
[cos(α+β)=cosαcosβ-sinαsinβ]
cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ
=1-2 (3/5)²
=1-2(9/25)
=1-18/25
=(25-18)/25
=7/25
