Help with parallel lines, please?

1 answer:

5 0

No, in order for the lines to be parallel, the slopes have to be the same, it does not matter what the slopes are as long as they are the same slope. The lines could still be parallel if the slopes are negative.

You might be interested in

I need this by tomorrow can someone help me, please

steposvetlana [31]

Answer:

no seeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeereeeeeeee

4 0

2 years ago

Read 2 more answers

Fully factorise 8p + 12

77julia77 [94]

$8p+12=4(2p+3)$

7 0

1 year ago

Read 2 more answers

Using 4 equal-width intervals, show that the trapezoidal rule is the average of the upper and lower sum estimates for the integr

prisoha [69]

Split up the interval [0, 2] into 4 subintervals, so that

$[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]$

Each subinterval has width $\dfrac{2-0}4=\dfrac12$ . The area of the trapezoid constructed on each subinterval is $\dfrac{f(x_i)+f(x_{i+1})}4$ , i.e. the average of the values of $x^2$ at both endpoints of the subinterval times 1/2 over each subinterval $[x_i,x_{i+1}]$ .

So,

$\displaystyle\int_0^2x^2\,\mathrm dx\approx\dfrac{0^2+\left(\frac12\right)^2}4+\dfrac{\left(\frac12\right)^2+1^2}4+\dfrac{1^2+\left(\frac32\right)^2}4+\dfrac{\left(\frac32\right)^2+2^2}4$

$=\displaystyle\sum_{i=1}^4\frac{\left(\frac{i-1}2\right)^2+\left(\frac i2\right)^2}4=\frac{11}4$

4 0

2 years ago

Which set of ordered pairs belongs to a linear function?

masya89 [10]

Answer:

<u><em>Hi there the correct answer will be is B) (-1,5), (1, 3), (3, 1), (5,0)</em></u>

hope it helps to your question!

7 0

3 years ago

Can someone run the answers alot of points given

ryzh [129]

2. 112
3. 0.08
4. idk if there is a decimal between the 2 and 4 if there is your answer is 4.08 if there isn't your answer is 40.8
7. 0.04
8. 19.78

7 0

3 years ago