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oksano4ka [1.4K]
3 years ago
15

A model car is 3 3/4 inches long.using a scale of 1/2 inch=2 feet,find the actual length of the car

Mathematics
1 answer:
MaRussiya [10]3 years ago
8 0

Answer:

14.25 because for every 1/2 inch, the car is 2 feet.

Step-by-step explanation:

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A giraffe can run 32 miles per hour. What is the speed in feet per second? (1 mile = 5280 ft)
velikii [3]

Set up your conversion using dimensional analysis. That's just a fancy way of saying set up your values so you cancel what you don't need and keep what you do. If we want to convert miles per hour to feet per second, we need to convert the miles to feet using the fact that there are 5280 feet in 1 mile, and then convert the hours to seconds using the fact that there are 3600 seconds in an hour. Your set up will look like this (it's all about setting up the fractions correctly): \frac{32miles}{hour}*\frac{5280feet}{1mile}*\frac{1hour}{3600seconds}. If you look at that closely, you can see the there is a label of miles on the top in the first fraction and on the bottom in the second fraction. Those cancel each other out by reducing. Then in the bottom of the first fraction there is hours and in the top of the last fraction there is hours. Those cancel out. From top to bottom or bottom to top you can cancel like labels. This leaves us with feet in the top and seconds in the bottom. Now it's a matter of doing the math. You multiply straight across the top and straight across the bottom. \frac{168960feet}{3600seconds}. Simplifying you get 46.933 feet per second.

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3 years ago
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3 years ago
A 2X2 square is centered at the origin. It is dilated by a factor of 3. What are coordinates of the vertices of the square?
Vesna [10]

Answer:

The vertices are:

A' = (-3, -3)

B' = (3, -3)

C' = (3, 3)

D' = (-3, 3)

Step-by-step explanation:

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1),  B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

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D(-1, 1) = 3(-1, 1) = D'(-3, 3)

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3 years ago
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