we know that
p^2 is the the frequency of hba homozygote
we are given
frequency of hba homozygotes is 0.1
so,
p^2 =frequency of hba homozygotes
we can plug values
and we get
..............Answer
30,60,90,120
40,80,120
they will both " ash " in 120 seconds (thats 2 minutes)...so they will both ash at
10:42 a.m.
I = Prt, where P = $1,295; r = 7/100 = 0.07, t = 180/365
I = 1,295 x 0.07 x 180/365 = $44.70
Add: (3x2 - 5x + 6) + (9 - 8x - 4x2)
The givens should be arranged first before we can start answering.
3x2 - 5x + 6 plus
-4x2 - 8x + 9
= -x2 - 13x +15
Therefore, the answer to the question is E) -x2 - 13x +15
Answer: y= 2.38x^2 + 0.90x + 9.90
Step-by-step explanation:
A p e x
