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Bezzdna [24]
3 years ago
8

A ... has one triangular base and three triangular lateral faces.

Mathematics
2 answers:
Llana [10]3 years ago
7 0

Hope this help!!!

Have a nice day!!!

Nastasia [14]3 years ago
3 0

Answer:

that gy is rong dount do it

Step-by-step explanation:

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What is 1.23625 rounded to the nearest cent?
Art [367]
Answer:
1.23625 rounded would be 1.24
6 0
2 years ago
Read 2 more answers
DO NOT SEND ME PDFS OR I WILL REPORT ANSWER CORRECTLY FOR BRAINLIEST
Temka [501]

Answer:

D is the answer

Step-by-step explanation:

Because everyone wants smart phones so just make them all smart phones lol

8 0
2 years ago
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Sin(x+y)-sin(x-y)/cos(x+y)+cos(x-y)=tany<br> how do i verify this?
dsp73

Answer:

Step-by-step explanation:

Numerator

sin

x

cos

y

+

cos

x

sin

y

−

[

sin

x

cos

y

−

cos

x

sin

y

)

=

sin

x

cos

y

+

cos

x

sin

y

−

sin

x

cos

y

+

cos

x

sin

y

=

2

cos

x

sin

y

Denominator

cos

x

cos

y

−

sin

x

sin

y

+

cos

x

cos

y

+

sin

x

sin

y

=

cos

x

cos

y

−

sin

x

sin

y

+

cos

x

cos

y

+

sin

x

sin

y

=

2

cos

x

cos

y

---------------------------------------------------------------

left side can now be expressed as

2

cos

x

sin

y

2

cos

x

cos

y

=

2

cos

x

sin

y

2

cos

x

cos

y

=

sin

y

cos

y

and  

sin

y

cos

y

=

tan

y

=

right side hence proved

7 0
3 years ago
I don't know how to do this. Any help?
Brut [27]

Answer:

cos 37=x/b (second one)

sin 37= a/b (third one)

tan 37=a/x (sixth one)

Step-by-step explanation:

Cos is defined by the adjacent side over the hypotenuse. Cos 37 would be x/b. Clearly, that is option 2. Sin is defined by opposite over hypotenuse. Sin 37 would be a/b. That is the 3rd option. Tan is defined by opposite over adjacent. Tan 37 would be a/x or the 6th option.

7 0
3 years ago
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
 
Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
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